What does it mean when two events are disjoint?
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 25m
- 9. Hypothesis Testing for One Sample3h 29m
- 10. Hypothesis Testing for Two Samples4h 50m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- 11. Correlation1h 24m
- 12. Regression1h 50m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA1h 57m
4. Probability
Addition Rule
Problem 5.2.38b
Textbook Question
38. Getting to Work According to a survey, the probability that a randomly selected worker primarily rides a bicycle to work is 0.792. The probability that a randomly selected worker primarily takes public transportation to work is 0.071. (b) What is the probability that a randomly selected worker primarily neither rides a bicycle nor takes public transportation to work?
Verified step by step guidance1
Identify the given probabilities: the probability that a worker rides a bicycle to work is \$0.792\(, and the probability that a worker takes public transportation to work is \)0.071$.
Understand that the problem asks for the probability that a worker neither rides a bicycle nor takes public transportation. This means we want the probability of the complement of the union of these two events.
Calculate the combined probability of a worker either riding a bicycle or taking public transportation. Since these two events are mutually exclusive (a worker primarily uses one mode), add the probabilities: \(P(\text{bicycle or public transport}) = 0.792 + 0.071\).
Use the complement rule to find the probability that a worker neither rides a bicycle nor takes public transportation: \(P(\text{neither}) = 1 - P(\text{bicycle or public transport})\).
Substitute the sum from step 3 into the complement formula from step 4 to express the final probability.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Probability of Complementary Events
The probability of the complement of an event is 1 minus the probability of the event itself. If an event A represents workers who ride a bicycle or take public transportation, then the probability of neither is 1 minus the probability of A.
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Complementary Events
Addition Rule of Probability
When calculating the probability of either of two mutually exclusive events occurring, you add their individual probabilities. Here, since riding a bicycle and taking public transportation are distinct modes, their probabilities can be summed to find the total probability of either.
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Probability of Non-Mutually Exclusive Events
Mutually Exclusive Events
Two events are mutually exclusive if they cannot happen at the same time. In this question, a worker cannot primarily use both a bicycle and public transportation simultaneously, so these events are mutually exclusive, allowing direct addition of their probabilities.
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Probability of Mutually Exclusive Events
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