The average birth weight at a hospital is 6.5lbs. with a standard deviation of 1.4lbs. What is the lowest weight which would be considered significantly high? Hint: Range Rule of Thumb - Numbers which are 2 or more standard deviations away from the mean are considered "significant".
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 25m
- 9. Hypothesis Testing for One Sample3h 29m
- 10. Hypothesis Testing for Two Samples4h 50m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- 11. Correlation1h 24m
- 12. Regression1h 50m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA1h 57m
3. Describing Data Numerically
Interpreting Standard Deviation
Problem 2.4.36
Textbook Question
Using Chebychev’s Theorem Old Faithful is a famous geyser at Yellowstone National Park. From a sample with n = 100, the mean interval between Old Faithful’s eruptions is 101.56 minutes and the standard deviation is 42.69 minutes. Using Chebychev’s Theorem, determine at least how many of the intervals lasted between 16.18 minutes and 186.94 minutes. (Adapted from Geyser Times)
Verified step by step guidance1
Step 1: Recall Chebychev's Theorem, which states that for any dataset (regardless of distribution), at least \(1 - \frac{1}{k^2}\) of the data values lie within \(k\) standard deviations of the mean, where \(k > 1\).
Step 2: Calculate the number of standard deviations \(k\) that the given interval \([16.18, 186.94]\) spans from the mean. Use the formula \(k = \frac{|x - \mu|}{\sigma}\), where \(x\) is the boundary value, \(\mu\) is the mean, and \(\sigma\) is the standard deviation. Compute \(k\) for both boundaries: \(k = \frac{101.56 - 16.18}{42.69}\) and \(k = \frac{186.94 - 101.56}{42.69}\).
Step 3: Verify that the calculated \(k\) values for both boundaries are approximately equal (they should be, as the interval is symmetric around the mean). Use the larger \(k\) value for the next step.
Step 4: Apply Chebychev's Theorem to determine the proportion of data within \(k\) standard deviations. Substitute \(k\) into the formula \(1 - \frac{1}{k^2}\) to find the minimum proportion of data within the interval.
Step 5: Multiply the proportion obtained in Step 4 by the total sample size \(n = 100\) to determine the minimum number of intervals that lasted between 16.18 minutes and 186.94 minutes.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Chebyshev's Theorem
Chebyshev's Theorem states that for any dataset, regardless of its distribution, at least 1 - (1/k²) of the data values will fall within k standard deviations from the mean. This theorem is particularly useful for understanding the spread of data and making inferences about the proportion of values that lie within a certain range, especially when the distribution is unknown.
Mean and Standard Deviation
The mean is the average of a set of values, calculated by summing all values and dividing by the number of values. The standard deviation measures the amount of variation or dispersion in a set of values, indicating how much individual data points deviate from the mean. Together, these statistics provide a summary of the data's central tendency and variability.
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Interval Calculation
In the context of Chebyshev's Theorem, calculating the interval involves determining how many standard deviations the specified range (16.18 to 186.94 minutes) is from the mean (101.56 minutes). This calculation helps in applying the theorem to find the minimum proportion of data points that fall within this interval, allowing for a better understanding of the distribution of eruption intervals.
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