Skip to main content
Ch. 5 - Normal Probability Distributions
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 5, Problem 5.5.13

In Exercises 9–14, write the binomial probability in words. Then, use a continuity correction to convert the binomial probability to a normal distribution probability.


P(x ≤ 150)

Verified step by step guidance
1
Step 1: Understand the problem. The given problem involves a binomial probability, P(x ≤ 150), which means we are looking for the probability that the random variable x is less than or equal to 150 in a binomial distribution.
Step 2: Recall the conditions for using a normal approximation to a binomial distribution. The binomial distribution can be approximated by a normal distribution if the sample size is large enough, specifically if both np ≥ 5 and n(1-p) ≥ 5, where n is the number of trials and p is the probability of success.
Step 3: Apply the continuity correction. Since the binomial distribution is discrete and the normal distribution is continuous, we use a continuity correction. For P(x ≤ 150), we adjust the value to P(x ≤ 150.5) to account for the discrete-to-continuous transition.
Step 4: Standardize the value using the z-score formula. The z-score formula is z = (x - μ) / σ, where μ = np (mean of the binomial distribution) and σ = √(np(1-p)) (standard deviation of the binomial distribution). Substitute the values of n, p, and x = 150.5 into the formula to calculate the z-score.
Step 5: Use the standard normal distribution table or a statistical software to find the probability corresponding to the calculated z-score. This will give you the approximate probability for P(x ≤ 150) using the normal distribution with continuity correction.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
2m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Binomial Probability

Binomial probability refers to the likelihood of obtaining a fixed number of successes in a fixed number of independent Bernoulli trials, each with the same probability of success. It is calculated using the binomial formula, which incorporates the number of trials, the number of successes, and the probability of success. This concept is essential for understanding discrete outcomes in scenarios like coin flips or quality control in manufacturing.
Recommended video:
Guided course
06:39
Calculating Probabilities in a Binomial Distribution

Normal Distribution

The normal distribution is a continuous probability distribution characterized by its bell-shaped curve, defined by its mean and standard deviation. It is significant in statistics because many phenomena tend to approximate a normal distribution due to the Central Limit Theorem, which states that the sum of a large number of independent random variables will be normally distributed, regardless of the original distribution.
Recommended video:
06:23
Using the Normal Distribution to Approximate Binomial Probabilities

Continuity Correction

Continuity correction is a technique used when approximating a discrete probability distribution, like the binomial distribution, with a continuous distribution, such as the normal distribution. It involves adjusting the discrete value by 0.5 units to account for the fact that the normal distribution is continuous. This correction improves the accuracy of the approximation, especially when the number of trials is small or the probability of success is not extreme.
Recommended video:
06:23
Using the Normal Distribution to Approximate Binomial Probabilities
Related Practice
Textbook Question

In Exercises 1–4, a population has a mean mu and a standard deviation sigma. Find the mean and standard deviation of the sampling distribution of sample means with sample size n.


Mu = 150, sigma =25, n = 49

102
views
Textbook Question

Computing Probabilities for Normal Distributions In Exercises 1–6, the random variable x is normally distributed with mean mu=174 and standard deviation sigma=20. Find the indicated probability.


P(172 < x <192)

132
views
Textbook Question

Finding Probability In Exercises 47–56, find the indicated probability using the standard normal distribution. If convenient, use technology to find the probability.


P(- 1.54 < z < 1.54)

92
views
Textbook Question

Interpreting the Central Limit Theorem In Exercises 19–26, find the mean and standard deviation of the indicated sampling distribution of sample means. Then sketch a graph of the sampling distribution.


Renewable Energy During a recent period of two years, the day-ahead prices for renewable energy in Germany (in euros per mega-watt hour) have a mean of 31.58 and a standard deviation of 12.293. Random samples of size 75 are drawn from this population, and the mean of each sample is determined.

81
views
Textbook Question

Construction About 63% of the residents in a town are in favor of building a new high school. One hundred five residents are randomly selected. What is the probability that the sample proportion in favor of building a new school is less than 55%? Interpret your result.

92
views
Textbook Question

Graphical Analysis In Exercises 17–22, find the indicated z-score(s) shown in the graph.


" style="" width="260">

116
views