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Ch. 5 - Normal Probability Distributions
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 5, Problem 5.5.8

In Exercises 5–8, match the binomial probability statement with its corresponding normal distribution probability statement (a)–(d) after a continuity correction.
P(x<109)


a. P(x>109.5)
b. P(x<108.5)
c. P(x<109.5)
d. P(x>108.5)

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1
Step 1: Understand the problem. The task is to match a binomial probability statement with its corresponding normal distribution probability statement after applying a continuity correction. Continuity correction is used when approximating a discrete distribution (like binomial) with a continuous distribution (like normal).
Step 2: Recall the rule for continuity correction. When converting a discrete value to a continuous range, adjust the value by ±0.5 depending on the inequality. For example, P(x < k) in a binomial distribution becomes P(x < k - 0.5) in the normal distribution.
Step 3: Apply the continuity correction to the given binomial probability statement P(x < 109). Since the inequality is 'less than', subtract 0.5 from 109. This gives P(x < 108.5) in the normal distribution.
Step 4: Match the corrected normal distribution probability statement P(x < 108.5) with the corresponding option provided in the problem. From the options, this matches option (b).
Step 5: Verify the process by reviewing the continuity correction rule and ensuring the adjustment aligns with the inequality direction ('less than' in this case). This confirms the correct match is P(x < 108.5).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Binomial Distribution

The binomial distribution models the number of successes in a fixed number of independent Bernoulli trials, each with the same probability of success. It is characterized by two parameters: the number of trials (n) and the probability of success (p). Understanding this distribution is crucial for analyzing scenarios where outcomes are binary, such as success/failure or yes/no.
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Mean & Standard Deviation of Binomial Distribution

Normal Approximation to the Binomial

The normal approximation to the binomial distribution is used when the number of trials is large, allowing the binomial probabilities to be approximated by a normal distribution. This is particularly useful because normal distributions are easier to work with mathematically. The approximation is valid when both np and n(1-p) are greater than 5, ensuring that the distribution is not too skewed.
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Using the Normal Distribution to Approximate Binomial Probabilities

Continuity Correction

Continuity correction is applied when using a normal distribution to approximate a discrete distribution, such as the binomial. It involves adjusting the discrete values by 0.5 to account for the fact that the normal distribution is continuous. For example, to find P(X < k) in a binomial distribution, one would use P(X < k + 0.5) in the normal approximation to improve accuracy.
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Using the Normal Distribution to Approximate Binomial Probabilities
Related Practice
Textbook Question

In Exercises 39 and 40, determine whether the finite correction factor should be used. If so, use it in your calculations when you find the probability.


Old Faithful In a sample of 100 eruptions of the Old Faithful geyser at Yellowstone National Park, the mean interval between eruptions was 129.58 minutes and the standard deviation was 108.54 minutes. A random sample of size 30 is selected from this population. What is the probability that the mean interval between eruptions is between 120 minutes and 140 minutes?

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Textbook Question

In Exercises 9–14, write the binomial probability in words. Then, use a continuity correction to convert the binomial probability to a normal distribution probability.


P(55 < x < 60)

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Textbook Question

Testing a Drug A drug manufacturer claims that a drug cures a rare skin disease 75% of the time. The claim is checked by testing the drug on 100 patients. If at least 70 patients are cured, then this claim will be accepted. Use this information in Exercises 31 and 32.


Find the probability that the claim will be rejected, assuming that the manufacturer’s claim is true.

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Textbook Question

Finding Probability In Exercises 41–46, find the probability of z occurring in the shaded region of the standard normal distribution. If convenient, use technology to find the probability.


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Textbook Question

Finding Area

In Exercises 23–36, find the indicated area under the standard normal curve. If convenient, use technology to find the area.


To the right of z= -0.355

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Textbook Question

Milk Containers A machine is set to fill milk containers with a mean of 64 ounces and a standard deviation of 0.11 ounce. A random sample of 40 containers has a mean of 64.05 ounces. The machine needs to be reset when the mean of a random sample is unusual. Does the machine need to be reset? Explain.

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