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Ch. 5 - Normal Probability Distributions
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 5, Problem 5.4.40

In Exercises 39 and 40, determine whether the finite correction factor should be used. If so, use it in your calculations when you find the probability.


Old Faithful In a sample of 100 eruptions of the Old Faithful geyser at Yellowstone National Park, the mean interval between eruptions was 129.58 minutes and the standard deviation was 108.54 minutes. A random sample of size 30 is selected from this population. What is the probability that the mean interval between eruptions is between 120 minutes and 140 minutes?

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Determine whether the finite population correction factor (FPC) should be used. The FPC is applied when the sample size (n) is greater than 5% of the population size (N). If the population size is not provided, assume it is large enough to ignore the FPC unless otherwise stated.
Identify the parameters of the problem: the population mean (μ = 129.58 minutes), the population standard deviation (σ = 108.54 minutes), the sample size (n = 30), and the range of interest for the sample mean (120 minutes to 140 minutes).
Calculate the standard error of the mean (SE). The formula for SE is: σn. Substitute the values of σ and n into the formula.
Standardize the range of interest (120 to 140 minutes) into z-scores using the formula: X - μSE, where X is the value of interest, μ is the population mean, and SE is the standard error calculated in the previous step.
Use the z-scores to find the cumulative probabilities from the standard normal distribution table. Subtract the cumulative probability corresponding to the lower z-score (120 minutes) from the cumulative probability corresponding to the upper z-score (140 minutes) to find the probability that the sample mean falls within the given range.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Finite Correction Factor

The Finite Correction Factor (FCF) is used in statistics when sampling without replacement from a finite population. It adjusts the standard error of the sample mean to account for the fact that the sample size is a significant fraction of the total population. This is important when the sample size is more than 5% of the population, as it helps to provide a more accurate estimate of variability.
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Central Limit Theorem

The Central Limit Theorem (CLT) states that the distribution of the sample mean will approach a normal distribution as the sample size increases, regardless of the population's distribution, provided the sample size is sufficiently large (typically n ≥ 30). This theorem is crucial for calculating probabilities related to sample means, as it allows us to use normal distribution properties even when the original data is not normally distributed.
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Standard Error of the Mean

The Standard Error of the Mean (SEM) quantifies the amount of variability in the sample mean estimates from the true population mean. It is calculated by dividing the population standard deviation by the square root of the sample size. A smaller SEM indicates that the sample mean is a more precise estimate of the population mean, which is essential for determining probabilities in hypothesis testing and confidence intervals.
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Related Practice
Textbook Question

Interpreting the Central Limit Theorem In Exercises 19–26, find the mean and standard deviation of the indicated sampling distribution of sample means. Then sketch a graph of the sampling distribution.


Renewable Energy The zloty is the official currency of Poland. During a recent period of two years, the day-ahead prices for renewable energy in Poland (in zlotys per mega-watt hour) have a mean of 158.51 and a standard deviation of 33.424. Random samples of size 100 are drawn from this population, and the mean of each sample is determined. (Adapted from Multidisciplinary Digital Publishing Institute)

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Textbook Question

Conservation About 74% of the residents in a town say that they are making an effort to conserve water or electricity. One hundred ten residents are randomly selected. What is the probability that the sample proportion making an effort to conserve water or electricity is greater than 80%? Interpret your result.

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Textbook Question

Computing Probabilities for Normal Distributions In Exercises 1–6, the random variable x is normally distributed with mean mu=174 and standard deviation sigma=20. Find the indicated probability.


P(x > 182)

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Textbook Question

In Exercises 9–14, write the binomial probability in words. Then, use a continuity correction to convert the binomial probability to a normal distribution probability.


P(55 < x < 60)

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Textbook Question

Testing a Drug A drug manufacturer claims that a drug cures a rare skin disease 75% of the time. The claim is checked by testing the drug on 100 patients. If at least 70 patients are cured, then this claim will be accepted. Use this information in Exercises 31 and 32.


Find the probability that the claim will be rejected, assuming that the manufacturer’s claim is true.

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Textbook Question

In Exercises 5–8, match the binomial probability statement with its corresponding normal distribution probability statement (a)–(d) after a continuity correction.

P(x<109)


a. P(x>109.5)

b. P(x<108.5)

c. P(x<109.5)

d. P(x>108.5)

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