A giant water tank takes the shape of a cylinder. It has a radius of 2m2\operatorname{m} and a height of 5m5\operatorname{m}. How much water can this tank hold? Round to the nearest tenth of a m3\operatorname{m^3}.Cylinder: V=πr2hV=\pi r^2h

62.8 m ⁡ 3 62.8\operatorname{m}^3 62.8 m 3

A giant water tank takes the shape of a cylinder. It has a radius of 2 m 2\operatorname{m} and a height of 5 m 5\operatorname{m} . How much water can this tank hold? Round to the nearest tenth of a m 3 \operatorname{m^3} . Cylinder: V = π r 2 h V=\pi r^2h

For this problem, we have a giant water tank shaped like a cylinder, and it has a radius of two meters and a height of five meters. How much water can this tank hold? Rounded to the nearest tenth of a meter cubed. So our first step for solving this problem is to identify our known and unknown quantities. So we know the radius of the tank is two meters, and we know the height of the tank is five meters. But what we don't know is how much water the tank can hold. This would also be known as the volume of the tank. So let's go ahead and plug in our known quantities into the equation and then solve for our unknown. So what we don't know is v, but we do know r is two, and we know h is five. Simplifying, we get pi times two squared is four, and four times five is 20. And we also know that pi is roughly equal to 3.14. So 3.14 times 20 is 62.8. So the volume of our tank is 62.8 meters cubed, and that there is our final answer.

A giant water tank takes the shape of a cylinder. It has a radius of 2 m ⁡ 2\operatorname{m} and a height of 5 m ⁡ 5\operatorname{m} . How much water can this tank hold? Round to the nearest tenth of a m 3 ⁡ \operatorname{m^3} . Cylinder: V = π r 2 h V=\pi r^2h

62.8 m ⁡ 3 62.8\operatorname{m}^3 62.8 m 3

125.7 m ⁡ 3 125.7\operatorname{m}^3 125.7 m 3

157.1 m ⁡ 3 157.1\operatorname{m}^3 157.1 m 3

251.3 m ⁡ 3 251.3\operatorname{m}^3 251.3 m 3

3. Solving Word Problems

Formulas

Beginning & Intermediate Algebra

3. Solving Word Problems

Formulas

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Multiple Choice

A giant water tank takes the shape of a cylinder. It has a radius of $2 m$ and a height of $5 m$ . How much water can this tank hold? Round to the nearest tenth of a $m^{3}$ .
Cylinder: $V = π r^{2} h$

$125.7$\operatorname{m}$^3$

$157.1$\operatorname{m}$^3$

$62.8$\operatorname{m}$^3$

$251.3$\operatorname{m}$^3$

Verified step by step guidance

Identify the formula for the volume of a cylinder, which is given by: $V = \pi r^2 h$ where $V$ is the volume, $r$ is the radius, and $h$ is the height.

Substitute the given values for the radius and height into the formula. Here, the radius $r = 2$ meters and the height $h = 5$ meters, so the formula becomes: $V = \pi (2)^2 (5)$

Calculate the square of the radius: $(2)^2 = 4$

Multiply the squared radius by the height: $4 \times 5 = 20$

Multiply the result by $\pi$ to find the volume: $V = 20 \pi$ cubic meters. To get the numerical value, multiply 20 by the approximate value of $\pi \approx 3.1416$, then round your answer to the nearest tenth.

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Struggling with Beginning & Intermediate Algebra?

A giant water tank takes the shape of a cylinder. It has a radius of 2m2\(\operatorname{m}\) and a height of 5m5\(\operatorname{m}\). How much water can this tank hold? Round to the nearest tenth of a m3\(\operatorname{m^3}\).Cylinder: V=πr2hV=\(\pi\) r^2h

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A giant water tank takes the shape of a cylinder. It has a radius of $2 m$ and a height of $5 m$ . How much water can this tank hold? Round to the nearest tenth of a $m^{3}$ .
Cylinder: $V = π r^{2} h$