Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
2. Mendel's Laws of Inheritance
Probability and Genetics
Struggling with Genetics?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
In a family where both parents are heterozygous for a recessive genetic disorder (genotype Aa), what is the probability that, when a couple has two children, both children will be affected by the disorder?
A
1/4
B
1/8
C
1/2
D
1/16
Verified step by step guidance1
Identify the genotypes of the parents: both are heterozygous (Aa) for the recessive disorder, meaning each parent has one dominant (A) and one recessive (a) allele.
Determine the probability that a single child will be affected by the disorder. Since the disorder is recessive, the child must inherit two recessive alleles (aa) to be affected. Use a Punnett square to find this probability, which is the chance of inheriting 'a' from both parents.
Calculate the probability for one child to be affected: the chance of inheriting 'a' from one parent is 1/2, so the probability of 'aa' genotype is \(\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}\).
Since the two children are independent events, find the probability that both children are affected by multiplying the individual probabilities: \(\frac{1}{4} \times \frac{1}{4}\).
Express the final probability as a fraction, which represents the chance that both children will have the recessive disorder.
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Related Practice
Multiple Choice
In a population of cats, the allele for long tails (L) is dominant over the allele for short tails (l). If the frequency of the long tail allele (L) is 0.7 and the population is in Hardy-Weinberg equilibrium, what is the expected frequency of cats with long tails?
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Probability and Genetics practice set

