Describe how nondisjunction in human female gametes can give rise to Klinefelter and Turner syndrome offspring following fertilization by a normal male gamete.
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
6. Chromosomal Variation
Chromosomal Mutations: Aneuploidy
Problem 12
Textbook Question
An attached-X female fly, XXY, expresses the recessive X-linked white-eye mutation. It is crossed to a male fly that expresses the X-linked recessive miniature-wing mutation. Determine the outcome of this cross in terms of sex, eye color, and wing size of the offspring.
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Identify the genotypes of the parents: The attached-X female has two X chromosomes attached together and one Y chromosome (genotype: XXY), and she expresses the recessive white-eye mutation on her X chromosomes. The male has one X chromosome with the recessive miniature-wing mutation and one Y chromosome (genotype: X^m Y).
Determine the possible gametes produced by each parent: The attached-X female produces gametes with the attached X chromosomes together (X^w X^w) or a Y chromosome, while the male produces gametes with either the X chromosome carrying the miniature-wing mutation (X^m) or the Y chromosome.
Set up a Punnett square to combine the female and male gametes: The female gametes are either X^w X^w or Y, and the male gametes are X^m or Y. Cross these to find all possible offspring genotypes.
Analyze the genotype of each offspring to determine their sex and phenotype: Offspring with two X chromosomes (one from each parent) will be female, and those with one X and one Y will be male. Use the presence of recessive alleles on the X chromosomes to determine eye color (white if recessive) and wing size (miniature if recessive).
Summarize the phenotypes of the offspring by sex, eye color, and wing size based on the genotypes obtained from the Punnett square.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
X-linked Inheritance
X-linked inheritance refers to genes located on the X chromosome. Since males have one X and one Y chromosome, recessive mutations on the X chromosome are expressed in males if present. Females have two X chromosomes, so recessive traits are expressed only if both X chromosomes carry the mutation.
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X-Inactivation
Attached-X Chromosome Configuration
An attached-X female has both X chromosomes physically connected and inherited together as a unit. This affects the segregation of sex chromosomes during meiosis, influencing the sex and genotype of offspring differently than typical XX females.
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Regions of X Chromosomes
Phenotypic Expression of Recessive Mutations
Recessive mutations, such as white-eye and miniature-wing, are only phenotypically visible when no dominant allele is present. Understanding which offspring inherit these recessive alleles on the X chromosome helps predict their eye color and wing size.
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Mutations and Phenotypes
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