When cows have twin calves of unlike sex (fraternal twins), the female twin is usually sterile and has masculinized reproductive organs. This calf is referred to as a freemartin. In cows, twins may share a common placenta and thus fetal circulation. Predict why a freemartin develops.
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
6. Chromosomal Variation
Chromosomal Mutations: Aneuploidy
Problem 16
Textbook Question
Indicate the expected number of Barr bodies in interphase cells of individuals with Klinefelter syndrome, Turner syndrome, and karyotypes 47, XYY, 47, XXX, and 48, XXXX.
Verified step by step guidance1
Recall that a Barr body is an inactivated X chromosome found in the nuclei of cells with more than one X chromosome. The number of Barr bodies is always one less than the total number of X chromosomes present in the cell.
For Klinefelter syndrome (typically 47, XXY), count the number of X chromosomes (2) and subtract 1 to find the number of Barr bodies: \(\text{Barr bodies} = \text{number of X chromosomes} - 1\).
For Turner syndrome (typically 45, X), there is only one X chromosome, so apply the formula to find the number of Barr bodies.
For the karyotype 47, XYY, note the number of X chromosomes and apply the formula to determine the number of Barr bodies.
For the karyotypes 47, XXX and 48, XXXX, count the X chromosomes and subtract 1 to find the expected number of Barr bodies in each case.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Barr Body Formation and X-Chromosome Inactivation
Barr bodies are inactivated X chromosomes found in the nuclei of female cells and individuals with extra X chromosomes. This process, called X-chromosome inactivation, ensures dosage compensation by silencing all but one X chromosome in each cell. The number of Barr bodies equals the number of X chromosomes minus one.
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X-Inactivation
Klinefelter Syndrome and Turner Syndrome Karyotypes
Klinefelter syndrome typically involves a 47,XXY karyotype, where one X chromosome is inactivated, resulting in one Barr body. Turner syndrome involves a 45,X karyotype with only one X chromosome, so no Barr bodies are present. Understanding these syndromes helps predict Barr body counts based on sex chromosome composition.
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Human Sex Chromosomes
Sex Chromosome Aneuploidies and Their Impact on Barr Bodies
Aneuploidies like 47,XYY, 47,XXX, and 48,XXXX involve variations in sex chromosome number. In 47,XYY, no Barr bodies form since there is only one X chromosome. In 47,XXX and 48,XXXX, the number of Barr bodies equals the number of X chromosomes minus one, resulting in two and three Barr bodies respectively.
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