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Ch. 10 - Chi-Square Tests and the F-Distribution
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 10, Problem 10.3.22

Performing a Two-Sample F-Test In Exercises 19–26, (a) identify the claim and state H0 and Ha, (b) find the critical value and identify the rejection region, (c) find the test statistic F, (d) decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim. Assume the samples are random and independent, and the populations are normally distributed.


Heart Transplant Waiting Times The table at the left shows a sample of the waiting times (in days) for a heart transplant for two age groups. At α=0.05, can you conclude that the variances of the waiting times differ between the two age groups? (Adapted from Organ Procurement and Transplantation Network)


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Step 1: Identify the claim and state the hypotheses. The claim is that the variances of the waiting times differ between the two age groups (18–34 and 35–49). Therefore, the null hypothesis (H0) is that the variances are equal: \(\sigma\)_1^2 = \(\sigma\)_2^2, and the alternative hypothesis (Ha) is that the variances are not equal: \(\sigma\)_1^2 \(\neq\) \(\sigma\)_2^2.
Step 2: Calculate the sample variances for each age group. For each group, find the mean of the waiting times, then compute the variance using the formula s^2 = \(\frac{1}{n-1}\) \(\sum\) (x_i - \(\bar{x}\))^2 , where n is the sample size, x_i are the data points, and \(\bar{x}\) is the sample mean.
Step 3: Determine the critical value and rejection region. Since this is a two-tailed F-test at significance level \(\alpha\) = 0.05, find the critical values from the F-distribution table using degrees of freedom df_1 = n_1 - 1 and df_2 = n_2 - 1 for the two samples. The rejection region consists of values of the test statistic less than the lower critical value or greater than the upper critical value.
Step 4: Calculate the test statistic F. The test statistic is the ratio of the larger sample variance to the smaller sample variance: F = \(\frac{s_{larger}\)^2}{s_{smaller}^2} . This ensures the test statistic is always greater than or equal to 1.
Step 5: Make a decision and interpret the result. Compare the calculated F statistic to the critical values. If the test statistic falls into the rejection region, reject the null hypothesis; otherwise, fail to reject it. Then, interpret this decision in the context of the original claim about whether the variances of waiting times differ between the two age groups.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Two-Sample F-Test for Variances

The two-sample F-test compares the variances of two independent samples to determine if they come from populations with equal variances. The test statistic is the ratio of the larger sample variance to the smaller one, and it follows an F-distribution under the null hypothesis. This test is sensitive to the assumption of normality in the populations.
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Hypothesis Testing Framework

Hypothesis testing involves stating a null hypothesis (H0) and an alternative hypothesis (Ha), selecting a significance level (α), and determining a rejection region based on critical values. The test statistic is calculated from sample data and compared to the critical value to decide whether to reject H0 or fail to reject it, guiding conclusions about the population.
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Assumptions of the F-Test

The F-test assumes that the samples are independent, randomly selected, and drawn from normally distributed populations. Violations of these assumptions can affect the validity of the test results. Ensuring these conditions helps maintain the accuracy and reliability of conclusions about variance differences.
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Related Practice
Textbook Question

"Finding a Critical F-Value for a Right-Tailed Test In Exercises 5–8, find the critical F-value for a right-tailed test using the level of significance α and degrees of freedom d.f.N and d.f.D.


α=0.025, d.f.N=7, d.f.D=3"

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Textbook Question

Finding Expected Frequencies

In Exercises 7–12, (a) calculate the marginal frequencies and (b) find the expected frequency for each cell in the contingency table. Assume that the variables are independent.


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Textbook Question

Performing a Two-Sample F-Test In Exercises 19–26, (a) identify the claim and state H0 and Ha, (b) find the critical value and identify the rejection region, (c) find the test statistic F, (d) decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim. Assume the samples are random and independent, and the populations are normally distributed.


Annual Salaries An employment information service claims that the standard deviation of the annual salaries for public relations managers is less in Louisiana than in Florida. You select a sample of public relations managers from each state. The results of each survey are shown in the figure. At α=0.05, can you support the service’s claim? (Adapted from America’s Career InfoNet)


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Textbook Question

"In Exercises 13–18, test the claim about the difference between two population variances σ₁² and σ₂² at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed.


Claim: σ₁² = σ₂²; α = 0.05.

Sample statistics: s₁² = 310, n₁ = 7 and s₂² = 297, n₂ = 8"

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Textbook Question

Testing for Normality Using a chi-square goodness-of-fit test, you can decide, with some degree of certainty, whether a variable is normally distributed. In all chi-square tests for normality, the null and alternative hypotheses are as listed below.


H₀: The variable has a normal distribution.


Hₐ: The variable does not have a normal distribution.


To determine the expected frequencies when performing a chi-square test for normality, first estimate the mean and standard deviation of the frequency distribution. Then, use the mean and standard deviation to compute the z-score for each class boundary. Then, use the z-scores to calculate the area under the standard normal curve for each class. Multiplying the resulting class areas by the sample size yields the expected frequency for each class.In Exercises 17 and 18, (a) find the expected frequencies, (b) find the critical value and identify the rejection region, (c) find the chi-square test statistic, (d) decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim.


In Exercises 17 and 18, (a) find the expected frequencies, (b) find the critical value and identify the rejection region, (c) find the chi-square test statistic, (d) decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim.


Test Scores At α=0.05, test the claim that the 400 test scores shown in the frequency distribution are normally distributed.


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Textbook Question

Performing a Chi-Square Independence Test In Exercises 13–28, perform the indicated chi-square independence test by performing the steps below.

a. Identify the claim and state H₀ and Hₐ


b. Determine the degrees of freedom, find the critical value, and identify the rejection region.


c. Find the chi-square test statistic.


d. Decide whether to reject or fail to reject the null hypothesis.


e. Interpret the decision in the context of the original claim.


Choosing a College The contingency table shows the results of a survey asking 1858 parents and students of different incomes what their deciding factor was in choosing a college. At α=0.01, can you conclude that the deciding factor in choosing a college is related to the income of the family? (Adapted from Sallie Mae)


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