The ACT and SAT are two college entrance exams. The composite score on the ACT is approximately normally distributed with mean 21.1 and standard deviation 5.1. The composite score on the SAT is approximately normally distributed with mean 1026 and standard deviation 210. Suppose you scored 26 on the ACT and 1240 on the SAT. Which exam did you score better on? Justify your reasoning using the normal model.
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 25m
- 9. Hypothesis Testing for One Sample3h 29m
- 10. Hypothesis Testing for Two Samples4h 50m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- 11. Correlation1h 24m
- 12. Regression1h 50m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA1h 57m
6. Normal Distribution and Continuous Random Variables
Non-Standard Normal Distribution
Problem 7.4.7
Textbook Question
"In Problems 5–14, a discrete random variable is given. Assume the probability of the random variable will be approximated using the normal distribution. Describe the area under the normal curve that will be computed. For example, if we wish to compute the probability of finding at least five defective items in a shipment, we would approximate the probability by computing the area under the normal curve to the right of x = 4.5.
The probability that exactly eight defective parts are in the shipment
"
Verified step by step guidance1
Identify the discrete random variable of interest, which in this case is the number of defective parts in the shipment, and note that we want the probability that exactly 8 defective parts occur.
Since the variable is discrete, apply the continuity correction to approximate the probability using the normal distribution. For "exactly 8", consider the interval from 7.5 to 8.5 to capture the probability mass at 8.
Determine the mean (\$\mu\$) and standard deviation (\$\sigma\$) of the discrete random variable, which are necessary parameters for the normal approximation. These should be given or calculated from the problem context.
Convert the interval bounds 7.5 and 8.5 to their corresponding z-scores using the formula:
\[z = \frac{x - \mu}{\sigma}\]
where \$x\$ is the boundary value (7.5 or 8.5).
The probability that exactly 8 defective parts occur is approximated by the area under the normal curve between the two z-scores calculated. This corresponds to the probability \$P(7.5 < X < 8.5)\$ under the normal distribution.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Discrete to Continuous Approximation
When a discrete random variable is approximated by a continuous distribution like the normal, a continuity correction is applied. This involves adjusting the discrete value by ±0.5 to better estimate probabilities, since the normal distribution is continuous and the discrete variable takes integer values.
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Variance & Standard Deviation of Discrete Random Variables
Normal Distribution and Area Under the Curve
The normal distribution is a continuous probability distribution characterized by its bell-shaped curve. Probabilities correspond to areas under this curve over specific intervals. Calculating the probability of an event involves finding the area under the curve between or beyond certain points.
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Z-Scores from Probabilities
Probability of Exact Values Using Normal Approximation
To find the probability that a discrete variable equals a specific value using the normal approximation, compute the area under the normal curve between the continuity-corrected bounds (value - 0.5 and value + 0.5). This area approximates the probability of the exact discrete outcome.
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Using the Normal Distribution to Approximate Binomial Probabilities
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