M&Ms The following data represent the weights (in grams) of a simple random sample of 50 M&M plain candies. Determine the shape of the distribution of weights of M&Ms by drawing a frequency histogram. Find the mean and median. Which measure of central tendency better describes the weight of a plain M&M?
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 25m
- 9. Hypothesis Testing for One Sample3h 29m
- 10. Hypothesis Testing for Two Samples4h 50m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- 11. Correlation1h 24m
- 12. Regression1h 50m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA1h 57m
3. Describing Data Numerically
Median
Problem 3.1.12
Textbook Question
The median for the given set of six ordered data values is 26.5. What is the missing value? 7 12 21 ______ 41 50
Verified step by step guidance1
Identify the position of the median in an ordered data set with an even number of values. Since there are 6 values, the median is the average of the 3rd and 4th values.
Write the formula for the median in this case: \(\text{Median} = \frac{\text{3rd value} + \text{4th value}}{2}\).
Substitute the known median value and the known 3rd value into the formula: \$26.5 = \frac{21 + x}{2}\(, where \)x$ is the missing 4th value.
Multiply both sides of the equation by 2 to eliminate the denominator: \$2 \times 26.5 = 21 + x$.
Solve for \(x\) by subtracting 21 from both sides: \(x = 2 \times 26.5 - 21\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Median of a Data Set
The median is the middle value of an ordered data set. For an even number of values, it is the average of the two middle numbers. Understanding how to find the median helps identify the missing value when the median is given.
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Calculating the Median
Ordered Data
Data must be arranged in ascending or descending order before finding the median. This ensures the middle values are correctly identified, which is essential for solving problems involving medians.
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Solving for an Unknown Value
When a data set contains a missing value, algebraic methods can be used to find it by setting up an equation based on known statistics, such as the median, and solving for the unknown.
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Standard Deviation (σ) Unknown
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