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Ch. 6 - Normal Probability Distributions
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 6, Problem 6.4.15a

Ergonomics. Exercises 9–16 involve applications to ergonomics, as described in the Chapter Problem.


Doorway Height The Boeing 757-200 ER airliner carries 200 passengers and has doors with a height of 72 in. Heights of men are normally distributed with a mean of 68.6 in. and a standard deviation of 2.8 in. (based on Data Set 1 “Body Data” in Appendix B).


a. If a male passenger is randomly selected, find the probability that he can fit through the doorway without bending.

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Step 1: Identify the key components of the problem. The doorway height is 72 inches, the mean height of men is 68.6 inches, and the standard deviation is 2.8 inches. Heights are normally distributed, so we will use the standard normal distribution (Z-distribution) to solve this problem.
Step 2: Define the random variable X as the height of a randomly selected male passenger. To find the probability that a male passenger can fit through the doorway without bending, we need to calculate P(X ≤ 72).
Step 3: Standardize the random variable X to convert it into a Z-score using the formula: Z = (X - μ) / σ, where X is the value of interest (72 inches), μ is the mean (68.6 inches), and σ is the standard deviation (2.8 inches).
Step 4: Substitute the values into the Z-score formula: Z = (72 - 68.6) / 2.8. Simplify the numerator and divide by the standard deviation to compute the Z-score.
Step 5: Use a standard normal distribution table or a statistical software to find the cumulative probability corresponding to the calculated Z-score. This cumulative probability represents the probability that a randomly selected male passenger can fit through the doorway without bending.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Normal Distribution

Normal distribution is a probability distribution that is symmetric about the mean, depicting that data near the mean are more frequent in occurrence than data far from the mean. In this context, the heights of men are normally distributed, which allows us to use the properties of the normal curve to calculate probabilities related to height.
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Finding Standard Normal Probabilities using z-Table

Z-Score

A Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is calculated by subtracting the mean from the value and then dividing by the standard deviation. In this problem, the Z-score will help determine how many standard deviations a male passenger's height is from the mean, which is essential for finding the probability of fitting through the doorway.
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Probability Calculation

Probability calculation involves determining the likelihood of a specific event occurring. In this scenario, we need to calculate the probability that a randomly selected male passenger's height is less than or equal to the doorway height of 72 inches. This is done using the Z-score and standard normal distribution tables or software to find the corresponding probability.
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Related Practice
Textbook Question

College Presidents There are about 4200 college presidents in the United States, and they have annual incomes with a distribution that is skewed instead of being normal. Many different samples of 40 college presidents are randomly selected, and the mean annual income is computed for each sample.

a. What is the approximate shape of the distribution of the sample means (uniform, normal, skewed, other)?

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Textbook Question

Arm Circumferences Arm circumferences of adult men are normally distributed with a mean of 33.64 cm and a standard deviation of 4.14 cm (based on Data Set 1 “Body Data” in Appendix B). A sample of 25 men is randomly selected and the mean of the arm circumferences is obtained.

b. What is the mean of all such sample means?

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Textbook Question

Mensa Membership in Mensa requires a score in the top 2% on a standard intelligence test. The Wechsler IQ test is designed for a mean of 100 and a standard deviation of 15, and scores are normally distributed.


c. If 4 subjects take the Wechsler IQ test and they have a mean of 131 but the individual scores are lost, can we conclude that all 4 of them have scores of at least 131?

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Textbook Question

Ergonomics. Exercises 9–16 involve applications to ergonomics, as described in the Chapter Problem.


Designing Manholes According to the website www.torchmate.com, “manhole covers must be a minimum of 22 in. in diameter, but can be as much as 60 in. in diameter.” Assume that a manhole is constructed to have a circular opening with a diameter of 22 in. Men have shoulder widths that are normally distributed with a mean of 18.2 in. and a standard deviation of 1.0 in. (based on data from the National Health and Nutrition Examination Survey).


a. What percentage of men will fit into the manhole?

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Textbook Question

Sleepwalking Assume that 29.2% of people have sleepwalked (based on “Prevalence and Comorbidity of Nocturnal Wandering in the U.S. Adult General Population, by Ohayon et al., Neurology, Vol. 78, No. 20). Assume that in a random sample of 1480 adults, 455 have sleepwalked.


a. Assuming that the rate of 29.2% is correct, find the probability that 455 or more of the 1480 adults have sleepwalked.

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Textbook Question

In Exercises 7–10, use the same population of {4, 5, 9} that was used in Examples 2 and 5. As in Examples 2 and 5, assume that samples of size n = 2 are randomly selected with replacement.


Sampling Distribution of the Sample Variance


a. Find the value of the population variance σ2.

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