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Ch. 7 - Estimating Parameters and Determining Sample Sizes
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 7, Problem 7.3.5

Use the given information to find the number of degrees of freedom, the critical values X2L and X2R, and the confidence interval estimate of σ. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution:


Nicotine in Menthol Cigarettes 95% confidence; n = 25, s = 0.24 mg

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Step 1: Determine the degrees of freedom (df). The degrees of freedom for a chi-square distribution is calculated as df = n - 1, where n is the sample size. In this case, n = 25, so df = 25 - 1.
Step 2: Identify the critical values X2L and X2R. For a 95% confidence level, the chi-square critical values are found using a chi-square table or statistical software. Use the degrees of freedom (df = 24) and the confidence level (95%) to locate the values such that the area in the tails is 2.5% each (0.025 in the left tail and 0.025 in the right tail).
Step 3: Calculate the confidence interval for the population standard deviation (σ). The formula for the confidence interval of σ is: \( \sqrt{ \frac{(n-1)s^2}{X^2_R} } \leq \sigma \leq \sqrt{ \frac{(n-1)s^2}{X^2_L} } \), where \( X^2_R \) and \( X^2_L \) are the critical values, \( n \) is the sample size, and \( s \) is the sample standard deviation.
Step 4: Substitute the values into the formula. Use \( n = 25 \), \( s = 0.24 \), and the critical values \( X^2_R \) and \( X^2_L \) obtained from the chi-square table. Compute the numerator \( (n-1)s^2 \) and divide by the respective critical values.
Step 5: Take the square root of the results from Step 4 to find the lower and upper bounds of the confidence interval for \( \sigma \). This will give the range within which the population standard deviation is likely to fall with 95% confidence.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Degrees of Freedom

Degrees of freedom (df) refer to the number of independent values or quantities that can vary in an analysis without violating any constraints. In the context of a sample, df is typically calculated as the sample size minus one (n - 1). This concept is crucial for determining the appropriate statistical distribution to use when conducting hypothesis tests or constructing confidence intervals.
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Chi-Square Distribution

The Chi-Square distribution is a statistical distribution that is commonly used in hypothesis testing, particularly for tests involving variance and goodness-of-fit. It is defined by its degrees of freedom and is positively skewed. Critical values from the Chi-Square distribution are used to determine the boundaries for confidence intervals and hypothesis tests, especially when assessing the variability of a sample.
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Confidence Interval for Standard Deviation

A confidence interval for the standard deviation (σ) provides a range of values within which the true population standard deviation is likely to fall, based on sample data. For a normally distributed population, this interval can be calculated using the sample standard deviation and the Chi-Square distribution. The confidence level, such as 95%, indicates the probability that the interval contains the true parameter.
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Related Practice
Textbook Question

Atkins Weight Loss Program In a test of weight loss programs, 40 adults used the Atkins weight loss program. After 12 months, their mean weight loss was found to be 2.1 lb, with a standard deviation of 4.8 lb. Construct a 90% confidence interval estimate of the standard deviation of the weight loss for all such subjects. Does the confidence interval give us information about the effectiveness of the diet?

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Textbook Question

Finding Critical Values.


In Exercises 5–8, find the critical value z=a/2 that corresponds to the given confidence level.


90%

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Textbook Question

Critical Thinking. In Exercises 17–28, use the data and confidence level to construct a confidence interval estimate of p, then address the given question.


Births A random sample of 860 births in New York State included 426 boys. Construct a 95% confidence interval estimate of the proportion of boys in all births. It is believed that among all births, the proportion of boys is 0.512. Do these sample results provide strong evidence against that belief?

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Textbook Question

Ages of Moviegoers Find the sample size needed to estimate the mean age of movie patrons, given that we want 98% confidence that the sample mean is within 1.5 years of the population mean. Assume that sigma=19.6 years, based on a previous report from the Motion Picture Association of America. Could the sample be obtained from one movie at one theater?

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Textbook Question

"Critical Thinking. In Exercises 17–28, use the data and confidence level to construct a confidence interval estimate of p, then address the given question.


Internet Use A random sample of 5005 adults in the United States includes 751 who do not use the Internet (based on three Pew Research Center polls). Construct a 95% confidence interval estimate of the percentage of U.S. adults who do not use the Internet. Based on the result, does it appear that the percentage of U.S. adults who do not use the Internet is different from 48%, which was the percentage in the year 2000?"

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Textbook Question

Medical Malpractice In a study of 1228 randomly selected medical malpractice lawsuits, it was found that 856 of them were dropped or dismissed (based on data from the Physicians Insurers Association of America). Use the bootstrap method to construct a 95% confidence interval estimate of the proportion of lawsuits that are dropped or dismissed. Use 1000 bootstrap samples. How does the result compare to the confidence interval found in Exercise 16 “Medical Malpractice” from Section 7-1?

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