Indicate whether the graph of each equation is a circle, an ellipse, a hyperbola, or a parabola.
Table of contents
- 1. Review of Real Numbers2h 43m
- 2. Linear Equations and Inequalities5h 35m
- 3. Solving Word Problems2h 46m
- 4. Graphs and Functions5h 12m
- The Rectangular Coordinate System44m
- Graph Linear Equations in Two Variables24m
- Graph Linear Equations Using Intercepts23m
- Slope of a Line44m
- Slope-Intercept Form38m
- Point Slope Form22m
- Linear Inequalities in Two Variables28m
- Introduction to Relations and Functions53m
- Function Notation15m
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- 5. Systems of Linear Equations1h 53m
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- Rational Equations44m
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- 9. Roots, Radicals, and Complex Numbers3h 57m
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- 12. Conic Sections & Systems of Nonlinear Equations2h 24m
- 13. Sequences, Series, and the Binomial Theorem1h 51m
12. Conic Sections & Systems of Nonlinear Equations
Hyperbolas
Multiple Choice
Determine if the transverse axis is horizontal or vertical for the following hyperbolas.
A
Horizontal
B
Vertical
C
Cannot be determined
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Verified step by step guidance1
Rewrite the given equation in the standard form of a hyperbola by dividing both sides of the equation by 18: \(\frac{3x^2}{18} - \frac{y^2}{18} = \frac{18}{18}\).
Simplify the fractions to get: \(\frac{x^2}{6} - \frac{y^2}{18} = 1\).
Identify the form of the hyperbola. Since the \(x^2\) term is positive and comes first, and the \(y^2\) term is subtracted, the hyperbola is of the form \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\).
Recall that for hyperbolas in the form \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\), the transverse axis is horizontal, while for \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\), it is vertical.
Conclude that since the hyperbola matches the first form, the transverse axis is horizontal.
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