Skip to main content
Ch. 05 - Using Newton's Laws: Friction, Circular Motion, Drag Forces
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Not the one you use?Change textbook
Chapter 5, Problem 80

A coffee cup on the horizontal dashboard of a car slides forward when the driver decelerates from 45 km/h to rest in 3.5 s or less, but not if she decelerates in a longer time. What is the coefficient of static friction between the cup and the dash? Assume the road and the dashboard are level (horizontal).

Verified step by step guidance
1
Convert the initial velocity of the car from km/h to m/s. Use the conversion factor: \(1 \text{ km/h} = \frac{1}{3.6} \text{ m/s}\). Thus, \(v_i = 45 \text{ km/h} = \frac{45}{3.6} \text{ m/s}\).
Determine the acceleration required to bring the car to rest in 3.5 seconds. Use the kinematic equation \(a = \frac{v_f - v_i}{t}\), where \(v_f = 0 \text{ m/s}\) (final velocity), \(v_i\) is the initial velocity (calculated in step 1), and \(t = 3.5 \text{ s}\).
Recognize that the coffee cup slides forward when the deceleration exceeds the maximum static friction force. The maximum static friction force is given by \(f_s = \mu_s N\), where \(\mu_s\) is the coefficient of static friction and \(N\) is the normal force. On a horizontal surface, \(N = mg\), where \(m\) is the mass of the cup and \(g\) is the acceleration due to gravity (\(9.8 \text{ m/s}^2\)).
The force causing the deceleration of the car is \(F = ma\), where \(a\) is the acceleration (calculated in step 2). For the cup to remain stationary relative to the dashboard, the static friction force must equal or exceed this force. Thus, \(\mu_s mg \geq ma\).
Simplify the inequality \(\mu_s mg \geq ma\) to solve for \(\mu_s\). Cancel \(m\) from both sides (assuming \(m \neq 0\)), resulting in \(\mu_s \geq \frac{a}{g}\). Substitute the value of \(a\) (from step 2) and \(g = 9.8 \text{ m/s}^2\) to find \(\mu_s\).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Newton's First Law of Motion

Newton's First Law states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity unless acted upon by a net external force. In this scenario, the coffee cup slides forward due to the deceleration of the car, illustrating that the cup's inertia resists the change in motion.
Recommended video:
Guided course
04:46
Newton's 1st Law

Friction

Friction is the force that opposes the relative motion of two surfaces in contact. The coefficient of static friction quantifies the maximum frictional force that can act before an object begins to slide. In this case, it determines whether the cup remains stationary on the dashboard during deceleration.
Recommended video:
Guided course
08:11
Static Friction & Equilibrium

Deceleration and Acceleration

Deceleration is a form of acceleration that results in a decrease in velocity. The rate of deceleration affects the forces acting on the coffee cup. If the deceleration exceeds the maximum static friction force, the cup will slide, allowing us to calculate the coefficient of static friction based on the car's deceleration.
Recommended video:
Guided course
05:47
Intro to Acceleration
Related Practice
Textbook Question

A train traveling at a constant speed rounds a curve of radius 215 m. A lamp suspended from the ceiling swings out to an angle of 18.5° throughout the curve. What is the speed of the train? [Hint: See Example 4–15.]

1456
views
Textbook Question

The 70.0-kg climber in Fig. 5–53 is supported in the 'chimney' by the friction forces exerted on his shoes and back. The static coefficients of friction between his shoes and the wall, and between his back and the wall, are 0.80 and 0.60, respectively. What is the minimum normal force he must exert? Assume the walls are vertical and that the static friction forces are both at their maximum. Ignore his grip on the rope.

1406
views
Textbook Question

Tarzan plans to cross a gorge by swinging in an arc from a hanging vine (Fig. 5–50). If his arms are capable of exerting a force of 1350 N on the vine, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 78 kg and the vine is 4.8 m long.

1412
views
Textbook Question

The position of a particle moving in the xy plane is given by r\(\overrightarrow{r}\) = (2.0m) cos [(3.0 rad/s)t ] i^\(\hat{i}\) +(2.0m) sin [(3.0 rad/s)t ] j^\(\hat{j}\), where r is in meters and t is in seconds. Calculate the velocity and acceleration vectors as functions of time.

1711
views
Textbook Question

A 28.0-kg block is connected to an empty 2.00-kg bucket by a cord running over a frictionless pulley (Fig. 5–56). The coefficient of static friction between the table and the block is 0.42 and the coefficient of kinetic friction between the table and the block is 0.34. Sand is gradually added to the bucket until the system just begins to move. Calculate the acceleration of the system.

290
views
Textbook Question

A pilot performs an evasive maneuver by diving vertically at a constant 310 m/s. If he can withstand an acceleration of 9.0 g’s without blacking out, at what altitude must he begin to pull his plane out of the dive (moving in a vertical circular path) to avoid crashing into the sea?

1420
views