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Ch 23: The Electric Field
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 23, Problem 7

An electret is similar to a magnet, but rather than being permanently magnetized, it has a permanent electric dipole moment. Suppose a small electret with electric dipole moment 1.0×10−7 C m is 25 cm from a small ball charged to +25 nC, with the ball on the axis of the electric dipole. What is the magnitude of the electric force on the ball?

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1
Step 1: Understand the problem. The electret has a permanent electric dipole moment, and the charged ball is placed on the axis of the dipole. The goal is to calculate the magnitude of the electric force on the ball due to the dipole's electric field.
Step 2: Recall the formula for the electric field due to a dipole along its axis. The electric field at a distance \( r \) from the dipole along its axis is given by \( E = \frac{1}{4 \pi \epsilon_0} \cdot \frac{2p}{r^3} \), where \( p \) is the dipole moment and \( \epsilon_0 \) is the permittivity of free space.
Step 3: Substitute the given values into the formula for the electric field. The dipole moment \( p = 1.0 \times 10^{-7} \; \text{C} \cdot \text{m} \), the distance \( r = 25 \; \text{cm} = 0.25 \; \text{m} \), and \( \epsilon_0 = 8.85 \times 10^{-12} \; \text{C}^2 / \text{N} \cdot \text{m}^2 \). Plug these values into the formula for \( E \).
Step 4: Calculate the force on the charged ball using \( F = qE \), where \( q \) is the charge of the ball and \( E \) is the electric field. The charge of the ball is \( q = +25 \; \text{nC} = 25 \times 10^{-9} \; \text{C} \). Substitute \( q \) and \( E \) into the formula for \( F \).
Step 5: Perform the calculations step by step to find the magnitude of the force. Ensure units are consistent throughout the calculation (e.g., meters for distance, coulombs for charge). The result will give the magnitude of the electric force on the ball.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electric Dipole Moment

The electric dipole moment is a vector quantity that represents the separation of positive and negative charges in a system. It is defined as the product of the charge and the distance between the charges. In this case, the electret has a permanent dipole moment, which influences the electric field it generates and interacts with other charges, such as the charged ball.
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Coulomb's Law

Coulomb's Law describes the force between two point charges. It states that the magnitude of the electric force is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. This law is fundamental for calculating the force exerted on the charged ball by the electric field created by the electret.
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Electric Field of a Dipole

The electric field generated by an electric dipole decreases with distance and is characterized by its dependence on the dipole moment and the distance from the dipole. For a dipole aligned with the axis, the electric field at a point along the axis can be calculated using specific formulas that incorporate the dipole moment and the distance from the dipole, which is essential for determining the force on the charged ball.
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Related Practice
Textbook Question

The electric field strength 1.5 cm from an electric dipole, on the axis of the dipole, is 1.5×105 N/C. If the dipole is replaced by a single charge, what magnitude charge in nC will give the same field strength 1.5 cm away?

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Textbook Question

The electric field strength 1.5 cm from an electric dipole, on the axis of the dipole, is 1.5×105 N/C. What is the dipole moment in nC mm?

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Textbook Question

A 10-cm-long thin glass rod uniformly charged to +10 nC and a 10-cm-long thin plastic rod uniformly charged to −10 nC are placed side by side, 4.0 cm apart. What are the electric field strengths E1 to E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods?

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Textbook Question

A small glass bead charged to +6.0 nC is in the plane that bisects a thin, uniformly charged, 10-cm-long glass rod and is 4.0 cm from the rod's center. The bead is repelled from the rod with a force of 840 μN. What is the total charge on the rod?

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Textbook Question

An electric dipole is formed from two charges, ±q, spaced 1.0 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (x, y)=(0 cm, 10 cm) is 360 N/C. What is the charge q? Give your answer in nC.

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Textbook Question

Two 10-cm-long thin glass rods uniformly charged to +10 nC are placed side by side, 4.0 cm apart. What are the electric field strengths E1 to E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left along the line connecting the midpoints of the two rods?

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