Repeat Exercise 26 for samples of size 72 and 108. What happens to the mean and the standard deviation of the distribution of sample means as the sample size increases?
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 25m
- 9. Hypothesis Testing for One Sample3h 29m
- 10. Hypothesis Testing for Two Samples4h 50m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- 11. Correlation1h 24m
- 12. Regression1h 50m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA1h 57m
7. Sampling Distributions & Confidence Intervals: Mean
Confidence Intervals for Population Mean
Problem 8.12b
Textbook Question
The mean room rate for two adults for a random sample of 26 three-star hotels in Cincinnati has a sample standard deviation of \$31. Assume the population is normally distributed. (Adapted from Expedia)
Construct a 99% confidence interval for the population standard deviation.
Verified step by step guidance1
Step 1: Recognize that the problem involves constructing a confidence interval for the population standard deviation. Since the population is normally distributed, we will use the chi-square distribution for this calculation.
Step 2: Identify the given values: the sample size (n = 26), the sample standard deviation (s = \$31), and the confidence level (99%).
Step 3: Determine the degrees of freedom (df) for the chi-square distribution. The formula is: . Substitute the sample size to calculate df.
Step 4: Find the critical chi-square values for the 99% confidence level. Use a chi-square table or statistical software to find the values for (upper critical value) and (lower critical value), where .
Step 5: Use the formula for the confidence interval of the population standard deviation: . Substitute the values for n, s, and the critical chi-square values to calculate the interval.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Confidence Interval
A confidence interval is a range of values, derived from a sample statistic, that is likely to contain the population parameter with a specified level of confidence. For example, a 99% confidence interval suggests that if we were to take many samples and construct intervals in the same way, approximately 99% of those intervals would contain the true population parameter.
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Sample Standard Deviation
The sample standard deviation is a measure of the amount of variation or dispersion in a set of sample data points. It quantifies how much the individual data points deviate from the sample mean. In this context, it is used to estimate the variability of room rates among the sampled hotels, which is crucial for constructing the confidence interval.
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Chi-Square Distribution
The Chi-Square distribution is a statistical distribution that is used to estimate the variance of a population based on sample data. When constructing confidence intervals for population variances or standard deviations, the Chi-Square distribution is applied, particularly when the population is normally distributed, as is the case in this question.
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