Develop a sample of size n = 8 such that x̄ = 15 and s = 0.
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 25m
- 9. Hypothesis Testing for One Sample3h 29m
- 10. Hypothesis Testing for Two Samples4h 50m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- 11. Correlation1h 24m
- 12. Regression1h 50m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA1h 57m
3. Describing Data Numerically
Standard Deviation
Problem 3.4.14
Textbook Question
Quality Control A manufacturer of bolts has a qualitycontrol policy that requires it to destroy any bolts that are more than 2 standard deviations from the mean. The quality-control engineer knows that the bolts coming off the assembly line have a mean length of 8 cm with a standard deviation of 0.05 cm. For what lengths will a bolt be destroyed? 167
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Identify the mean (\(\mu\)) and standard deviation (\(\sigma\)) of the bolt lengths. Here, \(\mu = 8\) cm and \(\sigma = 0.05\) cm.
Understand that bolts more than 2 standard deviations from the mean will be destroyed. This means bolts with lengths less than \(\mu - 2\sigma\) or greater than \(\mu + 2\sigma\) will be rejected.
Calculate the lower limit for acceptable bolt length using the formula: \(\mu - 2\sigma\).
Calculate the upper limit for acceptable bolt length using the formula: \(\mu + 2\sigma\).
Conclude that any bolt with length less than the lower limit or greater than the upper limit will be destroyed according to the quality control policy.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Normal Distribution and Standard Deviation
The normal distribution is a symmetric, bell-shaped curve describing how data values are spread around the mean. Standard deviation measures the average distance of data points from the mean, indicating variability. In quality control, it helps determine acceptable ranges for product measurements.
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Control Limits in Quality Control
Control limits define the boundaries within which a product's measurements are considered acceptable. Typically set at a certain number of standard deviations from the mean (e.g., ±2 SD), values outside these limits indicate defects or out-of-spec products that should be rejected or destroyed.
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Central Limit Theorem
Application of Mean and Standard Deviation to Determine Rejection Criteria
Given the mean and standard deviation, the rejection criteria are calculated by adding and subtracting multiples of the standard deviation from the mean. For bolts, lengths beyond mean ± 2 standard deviations are destroyed, ensuring only bolts within the acceptable size range are kept.
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