Find the vertex and axis of symmetry and determine the direction that the parabola opens.
$y = {(x + 4)}^{2} - 9$

Parabola opens downwards; Vertex: $\left(-4,-9\right)$ ; Axis of symmetry: $x=-4$

Parabola opens upwards; Vertex: $(- 4, - 9)$ ; Axis of symmetry: $x = - 4$

Parabola opens upwards; Vertex: $open paren 4 comma negative 9 close paren$ ; Axis of symmetry: $x equals 4$

Parabola opens downwards; Vertex: $\left(4,-9\right)$ ; Axis of symmetry: $x=4$

Verified step by step guidance

Identify the given quadratic function in vertex form: $y = \left(x + 4\right)^2 - 9$.

Recall that the vertex form of a parabola is $y = a\left(x - h\right)^2 + k$, where $(h, k)$ is the vertex.

Rewrite the expression inside the parentheses to match the form $x - h$: since it is $x + 4$, this means $h = -4$.

The vertex is therefore at the point $(h, k) = (-4, -9)$.

Determine the direction the parabola opens by looking at the coefficient $a$ in front of the squared term. Here, $a = 1$ (positive), so the parabola opens upwards. The axis of symmetry is the vertical line $x = -4$.

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Find the vertex and axis of symmetry and determine the direction that the parabola opens. y=(x+4)2−9y=\left(x+4\right)^2-9

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Find the vertex and axis of symmetry and determine the direction that the parabola opens.
$y = {(x + 4)}^{2} - 9$