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Ch 13: Newton's Theory of Gravity
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 13, Problem 20a

You have been visiting a distant planet. Your measurements have determined that the planet's mass is twice that of earth but the free-fall acceleration at the surface is only one-fourth as large. What is the planet's radius?

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Start by recalling the formula for gravitational acceleration at the surface of a planet: g = (G)(M) radius .

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gravitational Acceleration

Gravitational acceleration is the acceleration experienced by an object due to the gravitational force exerted by a massive body, such as a planet. It is denoted by 'g' and varies depending on the mass of the planet and the distance from its center. On Earth, this value is approximately 9.81 m/s², but it can be different on other celestial bodies based on their mass and radius.
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Newton's Law of Universal Gravitation

Newton's Law of Universal Gravitation states that every point mass attracts every other point mass in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This law helps us understand how gravitational forces operate between two masses and is fundamental in calculating gravitational acceleration on different planets.
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Radius of a Planet

The radius of a planet is the distance from its center to its surface. It plays a crucial role in determining the gravitational force experienced at the surface. According to the relationship between mass, radius, and gravitational acceleration, if a planet's mass increases while its gravitational acceleration decreases, the radius must also change to maintain the balance dictated by gravitational laws.
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Related Practice
Textbook Question

A rocket is launched straight up from the earth's surface at a speed of 15,000 m/s. What is its speed when it is very far away from the earth?

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Textbook Question

A space station orbits the sun at the same distance as the earth but on the opposite side of the sun. A small probe is fired away from the station. What minimum speed does the probe need to escape the solar system?

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Textbook Question

Two stars, one twice as massive as the other, are 1.0 light year (ly) apart. One light year is the distance light travels in one year at the speed of light, 3.00 ✕ 108 m/s . The gravitational potential energy of this double-star system is - 8.0 ✕ 1034 J. What is the mass of the lighter star?

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Textbook Question

Nothing can escape the event horizon of a black hole, not even light. You can think of the event horizon as being the distance from a black hole at which the escape speed is the speed of light, 3.00 ✕ 10⁸ m/s, making all escape impossible. What is the radius of the event horizon for a black hole with a mass 5.0 times the mass of the sun? This distance is called the Schwarzschild radius.

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Textbook Question

A binary star system has two stars, each with the same mass as our sun, separated by 1.0 ✕ 1012 m. A comet is very far away and essentially at rest. Slowly but surely, gravity pulls the comet toward the stars. Suppose the comet travels along a trajectory that passes through the midpoint between the two stars. What is the comet's speed at the midpoint?

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Textbook Question

You have been visiting a distant planet. Your measurements have determined that the planet's mass is twice that of earth but the free-fall acceleration at the surface is only one-fourth as large. To get back to earth, you need to escape the planet. What minimum speed does your rocket need?

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