Skip to main content
Ch 37: The Foundations of Modern Physics
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 37, Problem 10a

An electron in a cathode-ray beam passes between 2.5-cm-long parallel-plate electrodes that are 5.0 mm apart. A 2.0 mT, 2.5-cm-wide magnetic field is perpendicular to the electric field between the plates. The electron passes through the electrodes without being deflected if the potential difference between the plates is 600 V. What is the electron's speed?

Verified step by step guidance
1
Identify the forces acting on the electron: The electron is subject to both an electric force due to the electric field between the plates and a magnetic force due to the magnetic field. For the electron to pass through without deflection, these forces must balance each other.
Write the expression for the electric force: The electric force \( F_E \) is given by \( F_E = eE \), where \( e \) is the charge of the electron and \( E \) is the electric field. The electric field \( E \) can be calculated using \( E = \frac{V}{d} \), where \( V \) is the potential difference (600 V) and \( d \) is the separation between the plates (5.0 mm or 0.005 m).
Write the expression for the magnetic force: The magnetic force \( F_B \) is given by \( F_B = e v B \), where \( v \) is the speed of the electron and \( B \) is the magnetic field strength (2.0 mT or 0.002 T).
Set the forces equal to each other: Since the electron is not deflected, the electric force and magnetic force must balance. Set \( F_E = F_B \), which gives \( eE = e v B \). Simplify this to \( E = v B \).
Solve for the electron's speed: Substitute \( E = \frac{V}{d} \) into \( E = v B \), giving \( \frac{V}{d} = v B \). Rearrange to solve for \( v \): \( v = \frac{V}{d B} \). Substitute the given values for \( V \), \( d \), and \( B \) to calculate the speed of the electron.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electric Field

An electric field is a region around charged particles where other charged particles experience a force. It is defined by the voltage difference between two points, which creates a force on charged particles like electrons. The strength of the electric field (E) can be calculated using the formula E = V/d, where V is the potential difference and d is the distance between the plates.
Recommended video:
Guided course
03:16
Intro to Electric Fields

Magnetic Field

A magnetic field is a vector field that exerts a force on moving charged particles, such as electrons. The force experienced by a charged particle in a magnetic field is given by the Lorentz force law, F = q(v × B), where q is the charge, v is the velocity of the particle, and B is the magnetic field strength. The direction of the force is perpendicular to both the velocity of the particle and the magnetic field.
Recommended video:
Guided course
05:30
Magnetic Fields and Magnetic Dipoles

Velocity of Charged Particles

The velocity of charged particles, like electrons, is crucial for understanding their motion in electric and magnetic fields. In this scenario, the electron's speed can be determined by balancing the electric force and the magnetic force acting on it. When these forces are equal and opposite, the particle moves in a straight line without deflection, allowing us to calculate its speed using the relationship between the electric field, magnetic field, and the forces involved.
Recommended video:
Guided course
06:36
Charging Objects
Related Practice
Textbook Question

A 0.80-μm-diameter oil droplet is observed between two parallel electrodes spaced 11 mm apart. The droplet hangs motionless if the upper electrode is 20 V more positive than the lower electrode. The density of the oil is 885 kg/m3. Does the droplet have a surplus or a deficit of electrons? How many?

1556
views
Textbook Question

A ceramic cube 3.0 cm on each side radiates heat at 630 W. At what wavelength, in μm, does its emission spectrum peak? Assume e=1.

921
views
Textbook Question

An electron in a cathode-ray beam passes between 2.5-cm-long parallel-plate electrodes that are 5.0 mm apart. A 2.0 mT, 2.5-cm-wide magnetic field is perpendicular to the electric field between the plates. The electron passes through the electrodes without being deflected if the potential difference between the plates is 600 V. If the potential difference between the plates is set to zero, what is the electron's radius of curvature in the magnetic field?

329
views
Textbook Question

A 2.0-cm-diameter metal sphere is glowing red, but a spectrum shows that its emission spectrum peaks at an infrared wavelength of 2.0 μm. How much power does the sphere radiate? Assume e=1 .

1021
views
Textbook Question

Electrons pass through the parallel electrodes shown in FIGURE EX37.9 with a speed of 5.0×106 m/s. What magnetic field strength and direction will allow the electrons to pass through without being deflected? Assume that the magnetic field is confined to the region between the electrodes.

88
views
Textbook Question

Determine the speed of a 15 MeV helium atom.

166
views