Skip to main content
Ch 02: Motion Along a Straight Line
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 2, Problem 23

The human body can survive an acceleration trauma incident (sudden stop) if the magnitude of the acceleration is less than 250250 m/s2. If you are in an automobile accident with an initial speed of 105105 km/h (6565 mi/h) and are stopped by an airbag that inflates from the dashboard, over what distance must the airbag stop you for you to survive the crash?

Verified step by step guidance
1
First, convert the initial speed from kilometers per hour to meters per second. Use the conversion factor: 1 km/h = 0.27778 m/s. Therefore, 105 km/h is equivalent to 105 * 0.27778 m/s.
Next, identify the final speed after the stop, which is 0 m/s since the car comes to a complete stop.
Use the formula for acceleration: \( a = \frac{v^2 - u^2}{2s} \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the stopping distance.
Rearrange the formula to solve for the stopping distance \( s \): \( s = \frac{v^2 - u^2}{2a} \). Substitute \( v = 0 \), \( u \) as the converted initial speed, and \( a = 250 \) m/s².
Calculate the stopping distance \( s \) using the values substituted into the rearranged formula. This will give you the minimum distance over which the airbag must stop you to ensure survival.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
2m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Acceleration

Acceleration is the rate of change of velocity of an object. It is a vector quantity, having both magnitude and direction, and is measured in meters per second squared (m/s²). In the context of the question, understanding acceleration is crucial to determine the deceleration needed to safely stop a person during a crash.
Recommended video:
Guided course
05:47
Intro to Acceleration

Kinematics Equations

Kinematics equations describe the motion of objects without considering the forces that cause the motion. They relate displacement, initial velocity, final velocity, acceleration, and time. For this problem, the equation v² = u² + 2as can be used to find the stopping distance, where v is final velocity, u is initial velocity, a is acceleration, and s is displacement.
Recommended video:
Guided course
08:25
Kinematics Equations

Conversion of Units

Conversion of units is essential for ensuring consistency in calculations. In this problem, the initial speed is given in kilometers per hour, which must be converted to meters per second to match the units of acceleration. This involves multiplying the speed by a conversion factor of 1000/3600 to convert km/h to m/s.
Recommended video:
Guided course
07:46
Unit Conversions
Related Practice
Textbook Question

An antelope moving with constant acceleration covers the distance between two points 70.070.0 m apart in 6.006.00 s. Its speed as it passes the second point is 15.015.0 m/s. What is its acceleration?

3320
views
Textbook Question

A pilot who accelerates at more than 4g4g begins to 'gray out' but doesn't completely lose consciousness. Assuming constant acceleration, what is the shortest time that a jet pilot starting from rest can take to reach Mach 44 (four times the speed of sound) without graying out? (Use 331331 m/s for the speed of sound in cold air.)

2037
views
Textbook Question

A car sits on an entrance ramp to a freeway, waiting for a break in the traffic. Then the driver accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 2020 m/s (4545 mi/h) when it reaches the end of the 120120-m-long ramp. What is the acceleration of the car?

2908
views
Textbook Question

A pilot who accelerates at more than 4g4g begins to 'gray out' but doesn't completely lose consciousness. How far would the plane travel during this period of acceleration? (Use 331331 m/s for the speed of sound in cold air.)

2320
views
Textbook Question

In the fastest measured tennis serve, the ball left the racquet at 73.1473.14 m/s. A served tennis ball is typically in contact with the racquet for 30.030.0 ms and starts from rest. Assume constant acceleration. What was the ball's acceleration during this serve?

3190
views
1
rank
Textbook Question

The fastest measured pitched baseball left the pitcher's hand at a speed of 45.045.0 m/s. If the pitcher was in contact with the ball over a distance of 1.501.50 m and produced constant acceleration, what acceleration did he give the ball?

2938
views