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Ch. 12 - Analysis of Variance
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 12, Problem 12.CQ.1

Cola Weights Data Set 37 “Cola Weights and Volumes” in Appendix B lists the weights (lb) of the contents of cans of cola from four different samples: (1) regular Coke, (2) Diet Coke, (3) regular Pepsi, and (4) Diet Pepsi. The results from analysis of variance are shown in the Minitab display below. What is the null hypothesis for this analysis of variance test? Based on the displayed results, what should you conclude about H_knot. What do you conclude about equality of the mean weights from the four samples?
Minitab ANOVA table showing significant F-value and P-value for cola weights analysis.

Verified step by step guidance
1
Step 1: Understand the null hypothesis (H₀) for an analysis of variance (ANOVA) test. The null hypothesis states that the mean weights of the contents of the cans from the four samples (regular Coke, Diet Coke, regular Pepsi, Diet Pepsi) are equal. Mathematically, H₀: μ₁ = μ₂ = μ₃ = μ₄, where μ represents the mean weight for each sample.
Step 2: Examine the Minitab output provided. Focus on the P-Value column, which is used to test the null hypothesis. The P-Value for the 'Factor' source is 0.000, which is significantly less than the common significance level of 0.05.
Step 3: Interpret the P-Value. Since the P-Value is less than 0.05, we reject the null hypothesis (H₀). This indicates that there is sufficient evidence to conclude that at least one of the mean weights is different from the others.
Step 4: Analyze the F-Value. The F-Value is 503.06, which is very large. A high F-Value further supports the conclusion that the variation between the group means is significant compared to the variation within the groups.
Step 5: Conclude about the equality of mean weights. Based on the results, we conclude that the mean weights of the contents of the cans from the four samples are not equal. There is a statistically significant difference in the mean weights among the four groups.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Null Hypothesis (H0)

The null hypothesis (H0) is a statement that there is no effect or no difference, and it serves as a starting point for statistical testing. In the context of the ANOVA test for the cola weights, H0 posits that the mean weights of the four cola samples (regular Coke, Diet Coke, regular Pepsi, and Diet Pepsi) are equal. Rejecting H0 suggests that at least one sample mean is different from the others.
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Step 1: Write Hypotheses

Analysis of Variance (ANOVA)

ANOVA is a statistical method used to compare the means of three or more groups to determine if at least one group mean is significantly different from the others. It assesses the variance within each group and between groups, providing an F-value that indicates the ratio of these variances. A significant F-value, as shown in the Minitab output, suggests that the group means are not all equal.
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P-Value

The P-value is a statistical measure that helps determine the significance of the results obtained from a hypothesis test. It represents the probability of observing the data, or something more extreme, assuming the null hypothesis is true. In the provided Minitab output, a P-value of 0.000 indicates strong evidence against the null hypothesis, leading to the conclusion that there are significant differences in the mean weights of the cola samples.
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Step 3: Get P-Value
Related Practice
Textbook Question

In Exercises 5–16, use analysis of variance for the indicated test.


Clancy, Rowling, and Tolstoy Ease of Reading Pages were randomly selected from three books: The Bear and the Dragon by Tom Clancy, Harry Potter and the Sorcerer’s Stone by J.K. Rowling, and War and Peace by Leo Tolstoy. Listed below are Flesch Reading Ease Scores for those pages. Use a 0.05 significance level to test the claim that pages from books by those three authors have the same mean Flesch Reading Ease score. Given that higher scores correspond to text that is easier to read, which author appears to be different, and how is that author different?


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Textbook Question

In Exercises 1–4, use the following listed measured amounts of chest compression (mm) from car crash tests (from Data Set 35 “Car Data” in Appendix B). Also shown are the SPSS results from analysis of variance. Assume that we plan to use a 0.05 significance level to test the claim that the different car sizes have the same mean amount of chest compression.

P-VALUE If we use a 0.05 significance level in analysis of variance with the sample data given in Exercise 1, what is the P-value? What should we conclude? If the four populations have means that do not appear to be the same, does the analysis of variance test enable us to identify which populations have means that are significantly different?

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Textbook Question

Cola Weights The displayed results from Exercise 1 are from one-way analysis of variance. What is it about this test that characterizes it as one-way analysis of variance instead of two-way analysis of variance?

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Textbook Question

Normal Quantile Plot The accompanying normal quantile plot was obtained from the longevity times of presidents. What does this graph tell us?

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Textbook Question

Car Crash Test Measurements If we use the data given in Exercise 1 with two-way analysis of variance and a 0.05 significance level, we get the accompanying display. What do you conclude?

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Textbook Question

Cola Weights For the four samples described in Exercise 1, the sample of regular Coke has a mean weight of 0.81682 lb, the sample of Diet Coke has a mean weight of 0.78479 lb, the sample of regular Pepsi has a mean weight of 0.82410 lb, and the sample of Diet Pepsi has a mean weight of 0.78386 lb. If we use analysis of variance and reach a conclusion to reject equality of the four sample means, can we then conclude that any of the specific samples have means that are significantly different from the others?

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