Write the first four terms of the following geometric sequence.
$a_{1} = - 8, r = - \frac{1}{2}$

$-8,4,-2,1,$\ldots$$

$-8,-$\frac{17}{2}$,-9,-$\frac{19}{2}$,$\ldots$$

$-8,$\frac$14,-$\frac$12,1,$\ldots$$

$-$\frac$12,4,-32,256,$\ldots$$

Verified step by step guidance

Identify the first term of the geometric sequence, which is given as $a_1 = -8$.

Note the common ratio $r = -\frac{1}{2}$, which means each term is obtained by multiplying the previous term by $-\frac{1}{2}$.

Find the second term by multiplying the first term by the common ratio: $a_2 = a_1 \times r = -8 \times \left(-\frac{1}{2}\right)$.

Find the third term by multiplying the second term by the common ratio: $a_3 = a_2 \times r$.

Find the fourth term by multiplying the third term by the common ratio: $a_4 = a_3 \times r$.

Master General Term of a Geometric Sequence Example 1 with a bite sized video explanation from Patrick Ford

Write the first four terms of the following geometric sequence.a1=−8,r=−12a_1=-8,r=-\(\frac\)12