A man stands on the roof of a 15.0-m-tall building and throws a r...

Question

A man stands on the roof of a 15.0-m-tall building and throws a rock with a speed of 30.0 m/s at an angle of 33.0° above the horizontal. Ignore air resistance. Calculate (d) Draw x-t, y-t, υx–t, and υy–t graphs for the motion.

Accepted Answer

Hi, everyone. Let's jump into it. So from sea level and Archer stands on the edge of a cliff that is 20 m above the ground, he fires an arrow with a speed of 70 m per second at an angle of degrees above the horizontal. Draw the X direction versus time wide direction versus time velocity in the X direction versus time and velocity in the Y direction versus time graphs for the motion of the arrow upon shooting. And we're gonna ignore air resistance. So what we need to figure out is we're gonna look at these graphs here and we want to determine which one is going to reflect the motion of the arrow. So if we first consider these X and Y graphs here, We will want to consider how the different forces acting on the arrow and how that's going to influence its motion. So we know it's given an initial speed of 70 m/s, but with no other forces acting on it in the, in the X axis and there's no air resistance, the motion should remain constant. However, in the Y axis, the Arrow will be affected by gravity so even though it's fired at a 58° angle upwards, like this gravity will start acting on it and pull it back down immediately. So we should get this sort of loop here is the arcs up and then back down. So if we take a look at some of our answers here, we can probably already guess that some of these are not going to be correct. So looking at the X and Y graphs, we know that in the X direction, there's supposed to be a constant increase of the position in the X direction because it has a forward velocity. So if we look at these answer choices, We can see this one this one indicates that there is no increase in the X direction as time passes. So that wouldn't be correct. This indicates that the arrow would somehow travel backwards in the X direction. So that doesn't make any sense. And again down here, same thing. So if we go back up to answer a, we can see, not only is there a linear increase as we would expect, but you can also see here that there is the wide direction movement as we saw over here. And you'll notice that it goes below the graph. Why does it do that? Because we are, the archer is standing on the edge of a cliff. So after the arrow arcs up and back down, it's actually falling below the cliff into the water at sea level. So we can safely conclude that answer A is going to be correct. Thank you very much.

A man stands on the roof of a 15.0-m-tall building and throws a rock with a speed of 30.0 m/s at an angle of 33.0° above the horizontal. Ignore air resistance. Calculate (d) Draw x-t, y-t, υx–t, and υy–t graphs for the motion.

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