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Ch 04: Newton's Laws of Motion
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 4, Problem 8b

You walk into an elevator, step onto a scale, and push the 'up' button. You recall that your normal weight is 625625 N. Draw a free-body diagram. If you hold a 3.853.85-kg package by a light vertical string, what will be the tension in this string when the elevator accelerates as in part (a)? Note: Part (a) asked what does the scale read when the elevator has an upward acceleration of magnitude 2.502.50 m/s2.

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Step 1: Begin by analyzing the forces acting on you in the elevator. Your normal weight is 625 N, which is the gravitational force acting downward. When the elevator accelerates upward, there is an additional force due to the acceleration. Draw a free-body diagram showing two forces: the gravitational force (weight) acting downward and the normal force exerted by the scale acting upward.
Step 2: Use Newton's second law of motion, \( F_{net} = ma \), to calculate the net force acting on you. The net force is the difference between the upward normal force (scale reading) and the downward gravitational force. Express this as \( F_{net} = F_{normal} - F_{gravity} \). Rearrange to find \( F_{normal} = F_{gravity} + ma \).
Step 3: For the package, consider the forces acting on it. The package has a gravitational force \( F_{gravity, package} = m_{package} g \) acting downward and a tension force \( T \) in the string acting upward. When the elevator accelerates upward, the net force on the package is \( F_{net, package} = m_{package} a \). Use Newton's second law to express the tension in the string as \( T = F_{gravity, package} + m_{package} a \).
Step 4: Substitute the known values into the equations. For the package, \( m_{package} = 3.85 \, \text{kg} \) and \( g = 9.8 \, \text{m/s}^2 \). Calculate \( F_{gravity, package} = m_{package} g \). Then, use the acceleration \( a \) from part (a) to find the tension \( T \) in the string.
Step 5: Ensure all units are consistent and verify your calculations. The tension in the string depends on the elevator's acceleration \( a \), which you determined in part (a). Once \( a \) is known, substitute it into the equation for \( T \) to find the tension in the string.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Free-Body Diagram

A free-body diagram is a graphical representation used to visualize the forces acting on an object. In this context, it helps identify the forces on the person in the elevator, including gravitational force (weight) and the normal force from the scale. This diagram is essential for analyzing the net force and understanding how the forces interact during the elevator's acceleration.
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Newton's Second Law of Motion

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass, expressed as F = ma. This principle is crucial for determining the tension in the string when the elevator accelerates, as it allows us to calculate the net force acting on the package and how it relates to the forces of tension and gravity.
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Tension in a String

Tension is the force transmitted through a string, rope, or cable when it is pulled tight by forces acting from opposite ends. In this scenario, the tension in the string holding the package will vary depending on the elevator's acceleration. Understanding how to calculate tension involves considering both the weight of the package and the additional force due to the elevator's acceleration.
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Related Practice
Textbook Question

A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude 48.048.0 N to the box and produces an acceleration of magnitude 2.202.20 m/s2, what is the mass of the box?

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Textbook Question

You walk into an elevator, step onto a scale, and push the 'up' button. You recall that your normal weight is 625625 N. Draw a free-body diagram. When the elevator has an upward acceleration of magnitude 2.502.50 m/s2, what does the scale read?

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Textbook Question

A dockworker applies a constant horizontal force of 80.080.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.011.0 m in 5.00 5.00 s. What is the mass of the block of ice?

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Textbook Question

A man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a slope angle of 20.020.0°, and the man pulls upward with a force F\(\overrightarrow{F}\) whose direction makes an angle of 30.030.0° with the ramp (Fig. E4.44.4). How large a force F\(\overrightarrow{F}\) is necessary for the component FxF_{x} parallel to the ramp to be 90.090.0 N?

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Textbook Question

A man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a slope angle of 20.020.0°, and the man pulls upward with a force F\(\overrightarrow{F}\) whose direction makes an angle of 30.030.0° with the ramp (Fig. E4.44.4). How large will the component FyF_y perpendicular to the ramp be then?

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Textbook Question

A hockey puck with mass 0.1600.160 kg is at rest at the origin (x=0x = 0) on the horizontal, frictionless surface of the rink. At time t=0t = 0 a player applies a force of 0.2500.250 N to the puck, parallel to the xx-axis; she continues to apply this force until t=2.00t = 2.00 s. What are the position and speed of the puck at t=2.00t = 2.00 s?

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