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Ch 29: The Magnetic Field
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 29, Problem 44

When seen from the end, three long, parallel wires form an equilateral triangle 6.0 cm on a side. The wires each carry a 5.0 A current, with one current direction opposite the other two. What is the magnetic field strength at the center of the triangle?

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1
Convert the side length of the equilateral triangle from centimeters to meters. Since 1 cm = 0.01 m, the side length is 6.0 cm = 0.06 m.
Determine the distance from the center of the equilateral triangle to each wire. For an equilateral triangle, this distance (r) is given by \( r = \frac{a}{\sqrt{3}} \), where \( a \) is the side length. Substitute \( a = 0.06 \) m into the formula.
Use the Biot-Savart law to calculate the magnetic field contribution from each wire at the center. The magnetic field due to a long straight wire at a distance \( r \) is given by \( B = \frac{\mu_0 I}{2 \pi r} \), where \( \mu_0 = 4\pi \times 10^{-7} \, \text{T·m/A} \) is the permeability of free space, \( I \) is the current, and \( r \) is the distance calculated in the previous step.
Account for the direction of the magnetic fields. Use the right-hand rule to determine the direction of the magnetic field produced by each wire. Since two wires have currents in the same direction and one wire has a current in the opposite direction, their magnetic fields will combine vectorially. The symmetry of the equilateral triangle simplifies the vector addition.
Add the magnetic field contributions vectorially. The two wires with currents in the same direction will have their magnetic fields partially cancel the field from the wire with the opposite current. Use trigonometry to resolve the components and find the net magnetic field at the center of the triangle.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Magnetic Field Due to a Current-Carrying Wire

A current-carrying wire generates a magnetic field around it, described by the right-hand rule. The strength of the magnetic field (B) at a distance (r) from a long straight wire is given by the formula B = (μ₀I)/(2πr), where μ₀ is the permeability of free space and I is the current. This principle is essential for calculating the magnetic field contributions from each wire in the problem.
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Superposition of Magnetic Fields

The principle of superposition states that the total magnetic field at a point is the vector sum of the magnetic fields produced by each current-carrying wire. In this scenario, the magnetic fields from the three wires must be calculated individually and then combined, taking into account their directions, to find the net magnetic field at the center of the triangle.
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Equilateral Triangle Geometry

Understanding the geometry of an equilateral triangle is crucial for determining the distances from the center to each wire. In an equilateral triangle, the center (centroid) is equidistant from all three vertices. For a triangle with a side length of 6.0 cm, the distance from the center to each vertex can be calculated using geometric relationships, which is necessary for applying the magnetic field formula.
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