Finding z-Scores The distribution of the ages of the winners of the Tour de France from 1903 to 2020 is approximately bell-shaped. The mean age is 27.9 years, with a standard deviation of 3.4 years. In Exercises 43–48, use the corresponding z-score to determine whether the age is unusual. Explain your reasoning. (Source: Le Tour de France)
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 25m
- 9. Hypothesis Testing for One Sample3h 29m
- 10. Hypothesis Testing for Two Samples4h 50m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- 11. Correlation1h 24m
- 12. Regression1h 50m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA1h 57m
6. Normal Distribution and Continuous Random Variables
Probabilities & Z-Scores w/ Graphing Calculator
Problem 5.T.8
Textbook Question
The per capita disposable income for residents of a U.S. city in a recent year is normally distributed, with a mean of about \$44,000 and a standard deviation of about \$2450. Use this information in Exercises 7–10.
Out of 800 residents, about how many would you expect to have a disposable income of between \$40,000 and \$42,000?
Verified step by step guidance1
Step 1: Identify the key parameters of the normal distribution. The mean (μ) is \$44,000, and the standard deviation (σ) is \$2,450. The problem asks for the proportion of residents with disposable incomes between \$40,000 and \$42,000.
Step 2: Convert the income values (\$40,000 and \$42,000) into z-scores using the formula: , where x is the income value, μ is the mean, and σ is the standard deviation.
Step 3: Look up the z-scores in the standard normal distribution table (or use a calculator) to find the cumulative probabilities corresponding to the z-scores for \$40,000 and \$42,000.
Step 4: Calculate the proportion of residents with incomes between \$40,000 and \$42,000 by subtracting the cumulative probability for \$40,000 from the cumulative probability for \$42,000.
Step 5: Multiply the proportion obtained in Step 4 by the total number of residents (800) to estimate the number of residents with disposable incomes in the specified range.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Normal Distribution
Normal distribution is a probability distribution that is symmetric about the mean, indicating that data near the mean are more frequent in occurrence than data far from the mean. It is characterized by its bell-shaped curve, defined by its mean and standard deviation. In this context, the per capita disposable income follows a normal distribution, which allows us to use statistical methods to estimate probabilities and expectations.
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Z-Scores
A Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is calculated by subtracting the mean from the value and then dividing by the standard deviation. Z-scores are essential for determining how many standard deviations an element is from the mean, which is crucial for finding probabilities in a normal distribution.
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Empirical Rule
The Empirical Rule, also known as the 68-95-99.7 rule, states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% within two standard deviations, and 99.7% within three standard deviations. This rule helps in estimating the proportion of residents with disposable incomes within a specific range, such as between $40,000 and $42,000 in this scenario.
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