What is the magnetic field amplitude of an electromagnetic wave that has electric field amplitude $1500\text{V/m}$?

• A. $1.0\mu \mathrm{T}$
• B. $2.0\mu \mathrm{T}$
• C. $3.0\mu \mathrm{T}$
• D. $4.0\mu \mathrm{T}$
• E. $6.0\mu \mathrm{T}$
• F. $5.0\mu \mathrm{T}$

Answer: (F)

Verified step by step guidance

1. Understand that the relationship between the electric field (E) and the magnetic field (B) in an electromagnetic wave is given by the equation: E = cB, where c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s).
2. Rearrange the equation to solve for the magnetic field amplitude (B): B = E / c.
3. Substitute the given electric field amplitude (E = 1500 V/m) into the equation.
4. Use the value of the speed of light (c = 3.00 x 10^8 m/s) in the equation.
5. Calculate the magnetic field amplitude (B) using the values from the previous steps to find the correct answer.