The genotype of F1 individuals in a tetrahybrid cross is AaBbCcDd...

Question

The genotype of F1 individuals in a tetrahybrid cross is AaBbCcDd. Assuming independent assortment of these four genes, what are the probabilities that F2 offspring will have the following genotypes?
a. aabbccdd
b. AaBbCcDd
c. AABBCCDD
d. AaBBccDd
e. AaBBCCdd

Accepted Answer

Hi everyone here we have a question telling us to assume that in three genes undergoing independent source mint, the genotype of F one individuals involved in an tetra hybrid cross is capital A lowercase a capital B. Lowercase B capital C. Lower case E capital D. Lowercase D. Which of the following genotype will have an existing probability of of one out of 256 in the F two offspring. So we get one out of 256 by using our multiplication rule and multiplying 4th 4 times. Now, if we do a punnett square for a hetero saugus times ahead arose agus we will have a 1/4 chance of getting a homo zaius pair, whether it be dominant or recessive. So our answer is a possibility with all Homos Argus pairs. So our answer here is C. Thank you for watching. Bye.

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