Multiple Choice
In a Punnett square where both parents are heterozygous for unattached earlobes (Ee), what is the probability that the offspring in square 2 will have unattached earlobes?
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13. Mendelian Genetics
Punnett Square Probability
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A homozygous dominant male has a child with a heterozygous female. What is the probability that the child will have the same genotype as its father OR its mother?
A
½.
B
¼.
C
¾.
D
1.
Verified step by step guidance1
Identify the genotypes of the parents. The homozygous dominant male has the genotype 'AA', and the heterozygous female has the genotype 'Aa'.
Set up a Punnett square to determine the possible genotypes of the offspring. Place the alleles of one parent on the top and the alleles of the other parent on the side.
Fill in the Punnett square by combining the alleles from each parent. The possible genotypes for the offspring are 'AA' and 'Aa'.
Determine the probability of each genotype. There are two 'AA' squares and two 'Aa' squares, so the probability of 'AA' is 2/4 (or 1/2) and 'Aa' is 2/4 (or 1/2).
Calculate the probability that the child will have the same genotype as its father ('AA') or its mother ('Aa'). Add the probabilities: 1/2 (for 'AA') + 1/2 (for 'Aa') = 1.
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