In a population of 2500, how many babies would you expect to have cystic fibrosis, a homozygous recessive condition, if the frequency of the dominant allele is 0.9 and the population is at Hardy–Weinberg equilibrium?
a. 0.9×2500=2250
b. 2×0.9×0.1×2500=450
c. 0.9×0.1×2500=225
d. 0.1x0.1x2500=25
Verified Solution
This video solution was recommended by our tutors as helpful for the problem above.