Which of the following statements is true about the absolute maximum and minimum values of a continuous function on a closed interval ?
5. Graphical Applications of Derivatives
Intro to Extrema
- Multiple Choice74views
- Multiple Choice
In the context of extrema, if all the rates of change (derivatives) in a set of problems are negative, what does this indicate about the behavior of the functions involved?
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Which of the following best describes the difference between a relative maximum and an absolute maximum of a function on an interval ?
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Given the function , for which values of is the curve concave upward? (Select the correct interval.)
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For the function , at which -value does a local maximum occur?
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Finding Extreme Values
In Exercises 1–10, find the extreme values (absolute and local) of the function over its natural domain, and where they occur.
y = 𝓍³ ― 2𝓍 + 4
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A tangent line approximation of a function value is an underestimate when the function is:
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Given the function , which of the following statements correctly describes its local maxima, local minima, and saddle points?
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Determine where the local and absolute maxima and minima occur on the given graph of .
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Determine where the local and absolute maxima and minima occur on the given graph of .
393views2rank - Textbook Question
{Use of Tech} Optimal boxes Imagine a lidless box with height h and a square base whose sides have length x. The box must have a volume of 125 ft³.
b. Based on your graph in part (a), estimate the value of x that produces the box with a minimum surface area.
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Locating critical points Find the critical points of the following functions. Assume a is a nonzero constant.
ƒ(x) = 3x² - 4x + 2
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Locating critical points Find the critical points of the following functions. Assume a is a nonzero constant.
ƒ(x) = x³ / 3 - 9x
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Locating critical points Find the critical points of the following functions. Assume a is a nonzero constant.
ƒ(x) = 3x³ + 3x² / 2 - 2x
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Locating critical points Find the critical points of the following functions. Assume a is a nonzero constant.
ƒ(x) = x³ -4a²x
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