Two point charges are separated by a distance of . If each charge has a magnitude of , what is the magnitude of the electrostatic force between them? (Assume vacuum, )
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Electric Charge
Struggling with Physics?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Four identical point charges, each of charge , are placed at the corners of a square of side . What is the magnitude of the net electric force experienced by one of the charges due to the other three?
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Verified step by step guidance1
Identify the charges and their positions: Four identical point charges, each with charge \(q\), are placed at the corners of a square with side length \(a\). We want to find the net force on one charge due to the other three.
Calculate the forces due to the two adjacent charges: Each adjacent charge is a distance \(a\) away. Use Coulomb's law for the magnitude of the force between two point charges:
\[F = \frac{1}{4\pi\epsilon_0} \frac{q^2}{a^2}\]
Since there are two adjacent charges, calculate the forces from each and note their directions (along the sides of the square).
Calculate the force due to the diagonally opposite charge: The diagonal distance between opposite corners of the square is \(a\sqrt{2}\). Use Coulomb's law again:
\[F_{diag} = \frac{1}{4\pi\epsilon_0} \frac{q^2}{(a\sqrt{2})^2} = \frac{1}{4\pi\epsilon_0} \frac{q^2}{2a^2}\]
This force acts along the diagonal direction.
Resolve the forces into components: Choose a coordinate system with the charge experiencing the force at the origin. The two adjacent forces act along the x and y axes, while the diagonal force acts at a 45° angle. Break the diagonal force into x and y components using trigonometry:
\[F_{diag,x} = F_{diag} \cos 45^\circ, \quad F_{diag,y} = F_{diag} \sin 45^\circ\]
Sum the components of all forces: Add the x-components of the two adjacent forces and the diagonal force to get the total x-component of the net force. Do the same for the y-components. Then, find the magnitude of the net force using the Pythagorean theorem:
\[F_{net} = \sqrt{(F_x)^2 + (F_y)^2}\]
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