A simple circuit consists of a $12 V$ battery connected in series with a $4 \Omega$ resistor. What is the current in this circuit?

• A. $48$ A
• B. $3$ A
• C. $\frac{4}{12}$ A
• D. $\frac{12}{4}$ A

Answer: (D)

Verified step by step guidance

1. Identify the given quantities: the voltage of the battery \(V = 12\ \text{V}\) and the resistance of the resistor \(R = 4\ \Omega\).
2. Recall Ohm's Law, which relates voltage (\(V\)), current (\(I\)), and resistance (\(R\)) in a circuit: \(V = I \times R\).
3. Rearrange Ohm's Law to solve for the current \(I\): \(I = \frac{V}{R}\).
4. Substitute the known values into the equation: \(I = \frac{12}{4}\).
5. Express the current \(I\) as the quotient of the voltage and resistance, which gives the current flowing through the circuit.