Four resistors with resistances $R_1$, $R_2$, $R_3$, and $R_4$ are connected in series to a battery with voltage $V$. What is the total current flowing through the circuit?

• A. $\frac{V}{R_1\wedge R_2\wedge R_3\wedge R_4}$
• B. $\frac{V}{R_4}$
• C. $\frac{V}{R_1+R_2+R_3+R_4}$
• D. $\frac{V}{R_1}$

Answer: (C)

Verified step by step guidance

1. Identify that the four resistors R_1, R_2, R_3, and R_4 are connected in series, which means the total resistance is the sum of the individual resistances.
2. Write the formula for the total resistance in a series circuit: \(R_{\text{total}} = R_1 + R_2 + R_3 + R_4\).
3. Recall Ohm's Law, which relates voltage (V), current (I), and resistance (R) as \(V = IR\).
4. Rearrange Ohm's Law to solve for the current: \(I = \frac{V}{R}\).
5. Substitute the total resistance into the current formula to find the total current flowing through the circuit: \(I = \frac{V}{R_1 + R_2 + R_3 + R_4}\).