A baseball of mass $0.135\mathrm{kg}$ is thrown with a speed of $40.0m/s$. What is its kinetic energy?

• A. $27J$
• B. $216J$
• C. $108J$
• D. $54J$

Answer: (C)

Verified step by step guidance

1. Identify the given quantities: mass \(m = 0.135\ \text{kg}\) and speed \(v = 40.0\ \text{m/s}\).
2. Recall the formula for kinetic energy, which is the energy an object has due to its motion: \(KE = \frac{1}{2} m v^2\)
3. Substitute the given values into the kinetic energy formula: \(KE = \frac{1}{2} \times 0.135 \times (40.0)^2\)
4. Calculate the square of the velocity: \((40.0)^2 = 1600\)
5. Multiply the values step-by-step to find the kinetic energy: \(KE = \frac{1}{2} \times 0.135 \times 1600\)