Multiple Choice
The pea plant (Pisum sativum) is a good choice for studying heredity because it:
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13. Mendelian Genetics
Introduction to Mendel's Experiments
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
An individual with the genotype AABbCcDD can make how many different kinds of gametes?
A
2
B
8
C
16
D
32
E
4
Verified step by step guidance1
Identify the genotype of the individual: AABbCcDD.
Determine the number of heterozygous gene pairs, as these will contribute to the variety of gametes. In this genotype, B and C are heterozygous (Bb and Cc).
Use the formula for calculating the number of different gametes: \(2^n\), where \(n\) is the number of heterozygous pairs.
Substitute the number of heterozygous pairs into the formula: \(2^2\), since there are two heterozygous pairs (Bb and Cc).
Calculate the result of \(2^2\) to determine the number of different kinds of gametes the individual can produce.
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