What is the ground-state electron configuration for lead (Pb, atomic number 82) using noble-gas shorthand?

• A. [Xe] $f^{14}{d}^{10}{s}^2{p}^4$
• B. [Rn] $s^2{p}^2$
• C. [Xe] $f^{14}{d}^{10}{s}^2{p}^2$
• D. [Kr] $d^{10}{s}^2{p}^2$

Answer: (C)