Strong Acid Strong Base Titrations (Simplified) - Video Tutorials & Practice Problems
On a tight schedule?
Get a 10 bullets summary of the topic
Strong Acid-Base Titrations deal with stoichiometric calculations of chemical reactions involving neutralization between strong acids and bases.
Strong Acid Strong Base Titration
1
concept
Strong Acid Strong Base Titrations (Simplified) Concept 1
Video duration:
1m
Play a video:
now realize that when we talk about strong acid, strong based it rations that they deal with stark geometric calculations of chemical reactions involving neutralization between strong acids and bases. Were going to say what is neutralization though? Neutralization is where we have a chemical reaction in which the moles of acid and base reacts. Tokyo metric lee to one another. And what's important here in these types of penetration or neutralization reactions that strong acid neutralizes a strong acids neutralized basis. It doesn't matter if the bases are weak or strong, that's what they do in general and strong bases neutralize acids in general. Again, it doesn't matter if they're weak or strong. In this case we're focusing on strong acid and strong bases playing off of one another. Okay, we're not gonna talk about weak acids or weak bases being involved here. That's for a later discussion. So just realize that when we're talking about a strong acid strong based filtration, all it really is is Tokuyama tree of acids and bases.
2
concept
Strong Acid Strong Base Titrations (Simplified) Concept 2
Video duration:
1m
Play a video:
So remember strong acid, strong based penetrations are just spoke geometric questions dealing with asses and bases. Because of that, we can use a stoke geometric chart. Now remember the chart uses the given quantity of an acid or base in this case to determine the unknown quantity of another acid or base. Here we have hcl so hydrochloric acid reacting with barium hydroxide to produce barium chloride and water were given this volume and molar itty of barium hydroxide were given this volume of HCM. And you're looking for the missing polarity realize here that looking at this equation from a stroke, geometric viewpoint tells us that are given amount that we start with is usually in more clarity. Or it could be given to us in grants or it can be given to us in moles. Now the polarity is usually coupled with volume. So it's usually leaders of polarity, leaders of polarity leads us directly into moles of giving. And remember just like the other Starkey metric charts we've seen once, you know, your moles have given, you would do the jump where you're gonna go from, moles have given two moles of unknown. And during this jump, you have to look do a multiple comparison, which means you have to use the coefficients in the balanced equation. Once you have your moles of unknown, you can go anywhere you want, you can use that to find the polarity of the unknown or you can even use it to find the grams of unknown. So if you've seen my videos on circuit metric charts before, this is kind of like a rehash. But now looking and focusing through the lens of an acid and a base undergoing penetration. Now that we've gone over the basic parts of it that we've seen before in earlier videos. Move onto the next video. Let's take a look at the example. Question
3
example
Strong Acid Strong Base Titrations (Simplified) Example 1
Video duration:
2m
Play a video:
So here it says, if it takes 25.13 mls a 0.3 to zero more barium hydroxide to titrate, 31 mls of a solution containing hydrochloric acid. What is the molar concentration of hydrochloric acid? Alright, so to solve this, we're gonna do the following steps. First thing we're gonna do is we're gonna convert the given quantity into moles of given are given quantity. Is this part here? Its volume of polarity. Think of this as a complete set of means multiply and remember that moles equals leaders, times more clarity. So, if I change these uh these mill leaders and to leaders and multiply them by the polarity, that will give me the moles of barium hydroxide. All right, so what I'm gonna do first is I'm gonna have .02513 leaders are converted into leaders already. Remember that the polarity means moles over leaders. So that's .3-0 moles of bearing hydroxide per one leader Leaders cancel out. And what I've just done is found the moles of given the moles of barium hydroxide. Now, step two says to do a multiple comparison to convert moles of giving it two moles of unknown. All right. So, we look at the balance equation, we put moles of barium hydroxide here on the bottom. So you can cancel out and moles of hydrochloric acid here on top. According to my balanced equation. For every one mole of barium hydroxide, we have two moles of hydrochloric acid. So these moles cancel out. Now at this point This will give me the moles of hydrochloric acid which are .0160832 moles. Mhm. Now, it says if necessary, convert the moles of unknown into the desired units. We have to go a step further. We have to find polarity. So if the polarity is required to divide the moles of unknown by its leaders. So I just found the moles of my unknown. But that's not my molar itty. That's not my Mueller concentration. I'm gonna take those moles. And I just found and been divided by its leaders. Hcl has 31 mls, which when you convert to leaders is 310.31 leaders Here. That will give me my molar itty as . moller hcl. So this will be my final answer for this particular question.
4
Problem
Problem
How many grams of HNO3 are required to completely neutralize 110.0 mL of 0.770 M LiOH?
A
0.0847 g
B
57.0 g
C
84.7 g
D
5.34 g
5
Problem
Problem
What is the molar mass of a 0.350 g sample of a HA acid if it requires 50.0 mL of 0.440 M Sr(OH)2 to completely neutralize it? A is used as a place holder for the unknown nonmetal of the acid.
