Based on your understanding of the solubility rules, which of the following ionic compounds will be insoluble? 

• A. Zinc chloride
• B. Manganese (V) chlorate
• C. Lead (II) sulfate
• D. Gallium acetate

Answer: (C)

Verified step by step guidance

1. Review the solubility rules for common ionic compounds. These rules help predict whether a compound will dissolve in water.
2. Identify the anions in each compound: chloride (Cl⁻) in zinc chloride, chlorate (ClO₃⁻) in manganese (V) chlorate, sulfate (SO₄²⁻) in lead (II) sulfate, and acetate (C₂H₃O₂⁻) in gallium acetate.
3. Apply the solubility rules: Chlorides are generally soluble, except for those of silver, lead, and mercury. Chlorates are typically soluble. Sulfates are generally soluble, except for those of barium, lead, calcium, and strontium. Acetates are generally soluble.
4. Determine the exceptions: Lead (II) sulfate is an exception to the sulfate solubility rule, making it insoluble in water.
5. Conclude that based on the solubility rules and exceptions, lead (II) sulfate is the compound that will be insoluble in water.