Which neutral atom is isoelectronic with $F^{+}$?

• A. Neon (Ne)
• B. Sodium (Na)
• C. Fluorine (F)
• D. Oxygen (O)

Answer: (A)

Verified step by step guidance

1. Understand the term 'isoelectronic': atoms or ions that have the same number of electrons are called isoelectronic.
2. Determine the number of electrons in the given species: Fluorine ion with a positive charge, written as \(F^{+}\), means fluorine has lost one electron. Since a neutral fluorine atom has 9 electrons, \(F^{+}\) has \$9 - 1 = 8$ electrons.
3. Identify the neutral atom with the same number of electrons: Look for a neutral atom that naturally has 8 electrons.
4. Recall the atomic numbers of the given options: Neon (Ne) has 10 electrons, Sodium (Na) has 11, Fluorine (F) has 9, and Oxygen (O) has 8 electrons.
5. Conclude that Oxygen (O), with 8 electrons, is isoelectronic with \(F^{+}\) because they both have the same number of electrons.