How many moles of sucrose are present in 2.00 L of a 0.500 M solution?

• A. 2.00 mol
• B. 0.250 mol
• C. 0.500 mol
• D. 1.00 mol

Answer: (D)

Verified step by step guidance

1. Identify the given information: the volume of the solution is 2.00 L and the molarity (M) of the sucrose solution is 0.500 M.
2. Recall the definition of molarity: Molarity (M) is the number of moles of solute per liter of solution, expressed as \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\).
3. Rearrange the molarity formula to solve for moles of solute: \(\text{moles of solute} = M \times \text{liters of solution}\).
4. Substitute the known values into the equation: \(\text{moles of sucrose} = 0.500\, M \times 2.00\, L\).
5. Multiply the molarity by the volume to find the number of moles of sucrose present in the solution.