Draw a Lewis Dot Structure that obeys the octet rule for the following compound:NH₂OH.

• A.
• B.
• C.
• D.

Answer: (D)

Verified step by step guidance

1. Identify the total number of valence electrons in NH2OH. Nitrogen (N) has 5 valence electrons, each hydrogen (H) has 1 valence electron, and oxygen (O) has 6 valence electrons. Therefore, the total is 5 + 2(1) + 6 + 1 = 14 valence electrons.
2. Determine the central atom. In NH2OH, nitrogen (N) is typically the central atom because it can form multiple bonds and is less electronegative than oxygen.
3. Arrange the atoms around the central nitrogen atom. Connect the nitrogen atom to the oxygen atom and the two hydrogen atoms. The oxygen atom will also be connected to one hydrogen atom.
4. Distribute the remaining valence electrons to satisfy the octet rule. Start by placing electrons around the oxygen atom to complete its octet, then distribute any remaining electrons around the nitrogen atom.
5. Check that all atoms have complete octets (except hydrogen, which follows the duet rule) and that the total number of electrons used equals the number of valence electrons calculated initially.