Textbook Question
State the number of valence electrons, bonding pairs, and lone pairs in each of the following Lewis structures: (6.6)c.
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10. Chemical Bonding
Lewis Dot Structures: Neutral Compounds (Simplified)
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Determine the Lewis Dot Structure for the following compound:H2Se.
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Verified step by step guidance1
Identify the total number of valence electrons in the compound. Hydrogen (H) has 1 valence electron and Selenium (Se) has 6 valence electrons. Therefore, H2Se has a total of 2(1) + 6 = 8 valence electrons.
Determine the central atom. In H2Se, Selenium (Se) is the central atom because it is less electronegative than Hydrogen (H) and can form more bonds.
Place the central atom (Se) in the center and arrange the Hydrogen atoms around it. Connect each Hydrogen atom to the Selenium atom with a single bond.
Distribute the remaining valence electrons around the central atom to satisfy the octet rule. After forming two single bonds with Hydrogen, Selenium will have 4 electrons left to complete its octet.
Ensure that all atoms have a complete valence shell. Hydrogen atoms are satisfied with 2 electrons each, and Selenium should have 8 electrons around it, including the bonding pairs.
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