Which weighs more, 5.00 g or 0.0225 mol of acetaminophen (C8H9O2)?

Verified step by step guidance

1. Determine the molar mass of acetaminophen (C_8H_9O_2) by adding the atomic masses of all the atoms in the formula: 8 carbon atoms, 9 hydrogen atoms, and 2 oxygen atoms.
2. Calculate the mass of 0.0225 moles of acetaminophen using the formula: mass = moles \times molar mass.
3. Compare the calculated mass of 0.0225 moles of acetaminophen with the given mass of 5.00 g.
4. Determine which of the two masses is greater based on the comparison.
5. Conclude which option, 5.00 g or 0.0225 mol of acetaminophen, weighs more.

Key Concepts

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). For acetaminophen (C8H9O2), the molar mass can be calculated by summing the atomic masses of its constituent elements: carbon (C), hydrogen (H), and oxygen (O). This value is essential for converting between grams and moles, allowing for comparisons of mass in different units.

Conversion Between Grams and Moles

To compare weights in grams and moles, one must convert moles to grams using the molar mass. The formula is: mass (g) = number of moles × molar mass (g/mol). This conversion is crucial for determining which quantity weighs more, as it allows for a direct comparison of the two measurements.

Comparative Weight Analysis

Comparative weight analysis involves evaluating two or more quantities to determine which is heavier. In this case, after converting 0.0225 moles of acetaminophen to grams using its molar mass, one can directly compare the resulting weight to the given 5.00 g. This analysis is fundamental in chemistry for understanding relationships between different forms of measurement.