26. Capacitors & Dielectrics
Intro To Dielectrics
3PRACTICE PROBLEM
A student totally fills the space between parallel capacitor plates with a square piece of glass. The capacitor has a capacitance of 75 nF and is permanently connected to a 9V battery. Glass has a dielectric constant of K = 7. i) Calculate the supplementary charge that will flow onto the plates due to the insertion of the piece of glass. ii) Calculate the charge generated on each side of the glass piece, and iii) determine the impact of the glass piece on the electric field between the plates.
A student totally fills the space between parallel capacitor plates with a square piece of glass. The capacitor has a capacitance of 75 nF and is permanently connected to a 9V battery. Glass has a dielectric constant of K = 7. i) Calculate the supplementary charge that will flow onto the plates due to the insertion of the piece of glass. ii) Calculate the charge generated on each side of the glass piece, and iii) determine the impact of the glass piece on the electric field between the plates.
ANSWERS OPTIONS
A
i) 4.05 × 10-6 C
ii) 4.05 × 10-6 C
iii) The electric field doesn't change when the piece of glass is inserted
ii) 4.05 × 10-6 C
iii) The electric field doesn't change when the piece of glass is inserted
B
i) 4.05 × 10-6 C
ii) 4.05 × 10-6 C
iii) The electric field is multiplied by 7 when the piece of glass is inserted
ii) 4.05 × 10-6 C
iii) The electric field is multiplied by 7 when the piece of glass is inserted
C
i) 2.83× 10-6 C
ii) 2.83 × 10-6 C
iii) The electric field doesn't change when the piece of glass is inserted
ii) 2.83 × 10-6 C
iii) The electric field doesn't change when the piece of glass is inserted
D
i) 2.83× 10-6 C
ii) 2.83 × 10-6 C
iii) The electric field is multiplied by 7 when the piece of glass is inserted
ii) 2.83 × 10-6 C
iii) The electric field is multiplied by 7 when the piece of glass is inserted