The circular rod shown in the figure below is evenly charged with opposite charges of +Q and -Q on its two halves. Determine the electric potential at a point represented by the dot.
The overlap area between two parallel plates is 50. cm2. The separation of the plates is 2.0 mm. The plates are charged to create an electric field strength of 8.0 × 104 V/m between them. Determine the total charge on the plates.
Two parallel plates form a capacitor with a plate area of 12.0 cm2 and a separation distance of 1.20 mm. The plates are charged to a net charge of ±0.708 µC. (i) Calculate the electric field strength between the plates. Note: assume even electric field distribution between the plates. (ii) Find the electric potential difference between the plates.
A parallel plate capacitor is assembled using two square plates with a side length of 5.0 cm and a spacing of 1.0 mm between the plates. The electric field strength between the plates is 4.0 × 107 V/m. If a proton is shot from the negative plate towards the positive plate and arrives moving at 3.2 × 106 m/s, what was the proton's speed as it left the negative plate?
Suppose there are two point charges, one with a positive charge of +30 nC and the other with a negative charge of -20 nC. A distance of 6.0 cm separates these charges. An electron is initially at rest and released from a position equidistant between the charges. Calculate the speed of the electron after it has travelled a distance of 2.0 cm.