16. Chemical Equilibrium
Equilibrium Constant Calculations
Practice this topic
- Multiple Choice
The reaction: 2 NO(g) + Br2(g) ⇌ 2 NOBr(g), has a Kp of 2.5 x 102 at 35°C. Calculate the equilibrium concentration of NOBr, if equilibrium concentrations of NO and Br2 are 0.2 atm and 0.050 atm, respectively.
1026views19rank - Multiple Choice
For the reaction below, Kc = 1.5 at a constant temperature. A 3.2 L flask contains an equilibrium mixture of 3 compounds: 3.7 g of NH4HS, 70. g of NH3 and unknown amount of H2S. What is the mass (grams) of H2S produced at equilibrium?
NH4HS(s) ⇌ NH3(g) + H2S(g)
1048views26rank - Textbook Question
The diagram shown here represents the equilibrium state for the reaction A2(𝑔) + 2B(𝑔) ⇌ 2AB(𝑔). (a) Assuming the volume is 2 L, calculate the equilibrium constant 𝐾𝑐 for the reaction.
661views - Textbook Question
The following equilibria were attained at 823 K:
CoO(s) + H2(g) → Co(s) + H2O(g) Kc = 67
CoO(s) + CO(g) → Co(s) + CO2(g) Kc = 490
Based on these equilibria, calculate the equilibrium constant for H2(g) + CO2(g) → CO(g) + H2O(g) at 823 K.
127views - Textbook Question
Calculate the value of the equilibrium constant at 427 °C for the reaction
Na O1s2 + 1>2 O 1g2 ∆ Na O 1s2
given the following equilibrium constants at 427 °C.
Na2O1s2 ∆ 2 Na1l2 + 1>2 O21g2 Kc = 2 * 10-25 Na O 1s2 ∆ 2 Na1l2 + O 1g2 K = 5 * 10-29
128views - Textbook Question
Ethene (C2H4) can be halogenated by this reaction: C2H4(g) + X2(g) ⇌ C2H4X2(g) where X2 can be Cl2 (green), Br2 (brown), or I2 (purple). Examine the three figures representing equilibrium concentrations in this reaction at the same temperature for the three different hal- ogens. Rank the equilibrium constants for the three reactions from largest to smallest.
1448views1rank - Multiple ChoiceGiven the equilibrium CO(g) + H2O(g) ⇌ CO2(g) + H2(g) with an equilibrium constant (Keq) of 302 at 600K, what is the equilibrium constant for the reverse reaction CO2(g) + H2(g) ⇌ CO(g) + H2O(g) at the same temperature?399views
- Multiple ChoiceGiven the equilibrium expression 0.0611 = x^2 / ((1370 - x)(1710 - x)), what is the value of x at equilibrium?367views